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Genrish500 [490]
3 years ago
15

The combustion of methane gas (ch4) forms co2(g)+ h2o(ℓ). calculate the heat produced by burning 2 mol of the methane gas. use t

hese ∆h0 f data to help: ch4(g)= -74.9 kj/mol co2(g)= -393.5kj/mol h2o(ℓ)= -285.8kj/mol. answer in units of kj.
Chemistry
1 answer:
Nostrana [21]3 years ago
5 0
<span>Hess's Law is as follows. Note: Google Hess's law for the actual formula (i.e. with the Greek characters). ΔH(reaction) = Sum of ΔH(formation of products) - Sum of ΔH(formation of reactants) Now determine you're formula/reaction. In this case it's as follows: CH4 + 2 O2 -----> CO2 + 2 H2O The ΔH(formation) can be found in standardized tables, either online, in books, or provided to you. The ΔH you need for this is as follows in kJ/mol: CH4 (g) -75 O2 (g) 0 CO2 (g) -394 H2O (l) -286 When you plug the info into the formula you get the following: ΔH(reaction) = [(2*-238) + -394)] - [-75 + (2*0)] ΔH(reaction) = -891 kJ/mol Now you're looking for the amount of kJ for 1.65 mol. Your standard formula is as follows: E = ΔH(reaction) * mol where E is energy measured in kJ. So when you plug in your relevant values you get: E = -891 * 1.65 E = -1470.15 kJ</span>
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What is the pH of a solution that contains 25 grams of hydrochloric acid (hcl) dissolved in 1.5 liters of water?
Darina [25.2K]
First we calculate the concentration of HCl:

Moles = mass / Mr
= 25 / 36.5
= 0.685 mol

Concentration = 0.685/1.5 = 0.457 mol / dm³

For a strong monoprotic acid, the concentration of hydrogen ions is equal to the acid concentration.

pH = -log[H+]
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mariarad [96]
According to the reversible reaction equation:

2Hi(g) ↔ H2(g) + i2(g)

and when Keq is the concentration of the products / the concentration of the reactants.

Keq = [H2][i2]/[Hi]^2

when we have Keq = 1.67 x 10^-2

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so, by substitution:

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3 years ago
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