Answer:
Adding salt to the water increases the density of the solution because the salt increases the mass without changing the volume very much. When you add table salt (sodium chloride, NaCl) to water, the salt dissolves into ions, Na+ and Cl-. The volume increases by a small factor, but the mass increases by a bigger factor.
Explanation:
Answer:
See explanation
Explanation:
The drug thalidomide with molecular formula C13H10N2O4 was widely prescribed by doctors for morning sickness in pregnant women in the 1960s.
The drug was sold as a racemic mixture (+)(R)-thalidomide and (-)(S)-thalidomide.
Unfortunately, only the (+)(R)-thalidomide exhibited the required effect while (-)(S)-thalidomide is a teratogen.
This goes a long way to underscore the importance of separation of enantiomers in drug production.
Therefore, all the teratogenic effects observed when using the drug thalidomide was actually as a result of the presence of (-)(S)-thalidomide, the unwanted enantiomer.
Answer:
Weight of element X = 14.01 gram
Explanation:
Mass percentage is calculated by using :
![Percent =\frac{Mass\ of\ element}{Total\ mass}\times 100](https://tex.z-dn.net/?f=Percent%20%3D%5Cfrac%7BMass%5C%20of%5C%20element%7D%7BTotal%5C%20mass%7D%5Ctimes%20100)
![O\ Percent=\frac{Mass\ of\ O}{Total\ mass\ of\ XO2}\times 100](https://tex.z-dn.net/?f=O%5C%20Percent%3D%5Cfrac%7BMass%5C%20of%5C%20O%7D%7BTotal%5C%20mass%5C%20of%5C%20XO2%7D%5Ctimes%20100)
Mass of O = 16.0 gram
let mass of X = X grams = ?
Mass of XO2 = mass of X + 2(mass of O)
Mass of XO2 = X + 2(16)
Mass of XO2 = X + 32
Total mass of O in the compound = 2(16) = 32 grams
Percent O = 69.55 %
![Percent\ O =\frac{Mass\ of\ O}{Total\ mass\ of\ XO2}\times 100](https://tex.z-dn.net/?f=Percent%5C%20O%20%3D%5Cfrac%7BMass%5C%20of%5C%20O%7D%7BTotal%5C%20mass%5C%20of%5C%20XO2%7D%5Ctimes%20100)
![69.55=\frac{32}{X+32}\times 100](https://tex.z-dn.net/?f=69.55%3D%5Cfrac%7B32%7D%7BX%2B32%7D%5Ctimes%20100)
![\frac{69.55}{100}=\frac{32}{X+32}](https://tex.z-dn.net/?f=%5Cfrac%7B69.55%7D%7B100%7D%3D%5Cfrac%7B32%7D%7BX%2B32%7D)
![0.6955=\frac{32}{X+32}](https://tex.z-dn.net/?f=0.6955%3D%5Cfrac%7B32%7D%7BX%2B32%7D)
![0.6955\times (X+32)=32](https://tex.z-dn.net/?f=0.6955%5Ctimes%20%28X%2B32%29%3D32)
![0.6955X+ 22.256=32](https://tex.z-dn.net/?f=0.6955X%2B%2022.256%3D32)
![0.6955X=9.744](https://tex.z-dn.net/?f=0.6955X%3D9.744)
![X=\frac{9.744}{0.6955}](https://tex.z-dn.net/?f=X%3D%5Cfrac%7B9.744%7D%7B0.6955%7D)
![X =14.01](https://tex.z-dn.net/?f=X%20%3D14.01)
weight of element X = 14.01 gram
14.01 is mass of nitrogen N
The correct formula of this element is NO2