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2 years ago

6

7-¿Cuántos moles de CO2 estarán encerrados en un recipiente metálico a una presión de 1.10 Atm. y una temperatura de 31 °C, sabi

endo que el volumen del recipiente es de 15.70 litros?
8- De acuerdo con la ley combinada, dos litros de aire recogidos a 27 °C y 760 mmHg se
llevan a la cima del Pico Duarte donde la temperatura es 12 °C y la presión es 380 mmHg

Cuál es el nuevo volumen de la muestra del aire?

1 answer:

Aleks [24]2 years ago

4 0

Answer:

7- 0.69 moles.

8- El nuevo volumen es 3.8L.

Explanation:

7- Usando la ley general de los gases:

PV = nRT

PV / RT = n

<em>P es presión = 1.10atm</em>

<em>V es volumen = 15.70L</em>

<em>R es constante de los gases = 0.082atmL/molK</em>

<em>T es temperatura absoluta = 31°C + 273.15K = 304.15K</em>

<em />

Reemplazando:

1.10atm*15.70L / 0.082atmL/molK*304.15K = n

<h3>0.69 moles</h3><h3 />

8- La ley combinada de los gases establece como ecuación:

P1V1 / T1 = P2V2 / T2

<em>Donde P1 es la presión inicial = 760mmHg</em>

<em>V1 volumen inicial = 2L</em>

<em>T1 es temperatura absoluta = 273.15 + 27 = 300.15K</em>

<em>P2 = 380mmHg</em>

<em>T2 = 12°C + 273.15 = 285.15K</em>

<em />

Reemplazando:

760mmHg*2L / 300.15K = 380mmHg*V2 / 285.15K

3.8L = V2

<h3>El nuevo volumen es 3.8L</h3>

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<h3>Answer:</h3>

A saturated solution is a chemical solution containing the maximum concentration of a solute dissolved in the solvent.

<h3>Explanation:</h3>

A solution is made by dissolving a solute in a solvent.
For example dissolving a salt in a solvent such as water results to a solution.
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Unsaturated solution is a solution that can dissolve more solute upon addition because it has not reached saturation.
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Water has a boiling point of 100.0°C and a Kb of 0.512°C/m. What is the boiling

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The formula for molal boiling Point elevation is :

$\Delta T_{b} = iK_{b}m$

$\Delta T_{b}$ = elevation in boiling Point

$K_{b}$ = Boiling point constant( ebullioscopic constant)

m = molality of the solution

<em>i =</em> Van't Hoff Factor

Van't Hoff Factor = It takes into accounts,The abnormal values of Temperature change due to association and dissociation .

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$Mg_{3}(PO_{4})_{2}\rightarrow 3Mg^{2+} + 2 PO_{4}^{3-}$

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$\Delta T_{b} = iK_{b}m$

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