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Sedbober [7]
3 years ago
9

Jack crawled 3 ft and Christine crawled 3⁄4 the distance Jack crawled. If you add the distance they each crawled together, what

is the total distance the two children crawled. (Write the answer in inches.)
Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
5 0
Christine crawled:
3 ft* (3/4)= 2.25 ft.

3 ft+ 2.25 ft= 5.25 ft

We already know that 1 ft= 12 in.

5.25 ft* (12in/ 1 ft)= 63 in.

The total distance the two children crawled together is 63 in~
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<u>Answer</u><u> </u><u>:</u><u>-</u>

9(3+√3) feet

<u>Step </u><u>by</u><u> step</u><u> explanation</u><u> </u><u>:</u><u>-</u>

A triangle is given to us. In which one angle is 30° and length of one side is 18ft ( hypontenuse) .So here we can use trignometric Ratios to find values of rest sides. Let's lable the figure as ∆ABC .

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<u>Again</u><u> </u><u>In</u><u> </u><u>∆</u><u> </u><u>ABC</u><u> </u><u>,</u><u> </u>

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