The Decimal number system has following rules.
Suppose you have to write a number 4,567,892 .
2 -ones - (first period)
9-tens - (first period)
8-hundreds - (first period)
7-thousands - (second period)
6-ten thousand- (second period)
5-hundred thousand- (second period)
4-million- (third period)
then comes ten million,hundred million and then Billion.
If a number is given you have to apply commas from left to right after every three places.
So, your number is 9,418.
8-first period
1--first period
4--first period
9- second period
Answer:
Step-by-step explanation:
we know that
A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form 
or 
In this problem we have
y=18 when x=2
Find the value of the constant of proportionality k
----> 
therefore
The equation is equal to
The location of R on the number line will be 15/7.
Number line:
Number line is used for the visual representation of numbers on a straight line.
Basically, Zero (0) is considered to be the origin of a number line. The numbers to the left of 0 are negative numbers and the numbers to the right of 0 are all positive numbers.
Given,
On a number line,
point S is located at – 3 and
point T is located at 9.
Ratio of S and T = 3:4
We need to find the location of point R on S and T.
According to the given details,
The distance from S to T
=> 3 + 9 = 12
Through this we know that,
=> SR + RT = 12 ---------------------(1)
Based on the ratio,
S/T = 3/4
Which is similar to,
SR/RT = 3/4
So,
SR = 3/4 RT -----------(2)
Apply the value of SR on equation (1),
Then
3/4RT + RT = 12
=> 7/4 RT = 12
=> RT = 12 x (4/7)
=> RT = 48/7
Now the location of point R,
=> OT - RT = 9 - 48/7
=> 15/7
Hence "The location of R on the number line will be 15/7".
To know more about Number line Here
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we have a maximum at t = 0, where the maximum is y = 30.
We have a minimum at t = -1 and t = 1, where the minimum is y = 20.
<h3>
How to find the maximums and minimums?</h3>
These are given by the zeros of the first derivation.
In this case, the function is:
w(t) = 10t^4 - 20t^2 + 30.
The first derivation is:
w'(t) = 4*10t^3 - 2*20t
w'(t) = 40t^3 - 40t
The zeros are:
0 = 40t^3 - 40t
We can rewrite this as:
0 = t*(40t^2 - 40)
So one zero is at t = 0, the other two are given by:
0 = 40t^2 - 40
40/40 = t^2
±√1 = ±1 = t
So we have 3 roots:
t = -1, 0, 1
We can just evaluate the function in these 3 values to see which ones are maximums and minimums.
w(-1) = 10*(-1)^4 - 20*(-1)^2 + 30 = 10 - 20 + 30 = 20
w(0) = 10*0^4 - 20*0^2 + 30 = 30
w(1) = 10*(1)^4 - 20*(1)^2 + 30 = 20
So we have a maximum at x = 0, where the maximum is y = 30.
We have a minimum at x = -1 and x = 1, where the minimum is y = 20.
If you want to learn more about maximization, you can read:
brainly.com/question/19819849
