Answer:
Step-by-step explanation:
3) diameter of penny = 19 mm
r = 19/2 = 9.5 mm
Area of penny = πr²
= 3.14 * 9.5 * 9.5
= 283.385
= 283.39 mm²
Diameter of nickel = 21 mm
r = 21/2 = 10.5 mm
Area of nickel = πr²
= 3.14 * 10.5 *10.5
= 346.185
= 346.19 mm²
346.19 - 283.39 = 62.8 mm²
Area of Canadian nickel is greater than Canadian penny by 32.6 mm²
4) r = 12 mm
Area of circle = πr²
= 3.14 * 12 * 12
= 452.16 mm²
5) r = 20 cm
Area of circle = πr²
= 3.14 * 20 * 20
= 1256 cm²
Monthly depreciation is calculated as follows:
65,000 (Cost) – 5,000 (Salvage Value) ÷ 60 (5 years X 12 months per year) = 1,000 in depreciation per month.
a) Accumulated depreciation from 1/1/12 to 1/1/15 is 36,000 (12 months for 2012, 2013, & 2014).
Assuming that sale was a Cash sale, the journal entry would look like this:
1/1/15
Cash (DR) 31,000
Accumulated Depreciation (DR) 36,000
Equipment (CR) 65,000
Gain on Sale of Equipment (CR) 2,000
b) Accumulated depreciation from 1/1/12 to 5/1/15 is 40,000 (12 months for 2012, 2013, 2014, & 4 months for 2015).
Assuming that sale was a Cash sale, the journal entry would look like this:
5/1/15
Cash (DR) 31,000
Accumulated Depreciation (DR) 40,000
Equipment (CR) 65,000
Gain on Sale of Equipment (CR) 6,000
c) Accumulated depreciation from 1/1/12 to 1/1/15 is 36,000 (12 months for 2012, 2013, & 2014).
Assuming that sale was a Cash sale, the journal entry would look like this:
1/1/15
Cash (DR) 11,000
Accumulated Depreciation (DR) 36,000
Loss on Sale of Equipment (DR) 18,000
Equipment (CR) 65,000
d) Accumulated depreciation from 1/1/12 to 10/1/15 is 45,000 (12 months for 2012, 2013, 2014, & 9 months for 2015).
Assuming that sale was a Cash sale, the journal entry would look like this:
10/1/15
Cash (DR) 11,000
Accumulated Depreciation (DR) 45,000
Loss on Sale of Equipment (DR) 9,000
Equipment (CR) 65,000
Not my answers, but I hope this will help you. :)
It's 8/a^6 that's your answer
