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stich3 [128]
3 years ago
5

Pls help:((((

Mathematics
1 answer:
Fiesta28 [93]3 years ago
4 0

Answer: B

Step-by-step explanation:

l = 2

2 ( l + w ) = 48 , or , l + w = 24

w = 8 , & , so , l = 2 w = 16  inches.

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Solve: x + 1 &lt; 5<br>Me confused and need help ​
natita [175]

Answer: x < 4

Step-by-step explanation: You are trying to isolate the variable, x, so you have to subtract 1 on both sides of the inequality. Then, you are left with x < 4.

4 0
3 years ago
What is the vertex form, f(x) = a(x - h)2-k, for a parabola that passes through the point (2,8) and has (1,0) as its
Novay_Z [31]

Answer:

Step-by-step explanation:

hello :

f(x) = a(x - h)²-k   ....vertex form  when the vertex is : (h,k)

h=1  and  k=0   so : f(x) = a(x-1)²

a parabola that passes through the point (2,8) : f(2)=8

a(2-1)² =8

a= 8

f(x) = 8(x-1)²=  8(x²-2x+1)

f(x) 8x²-16x+8   .....standard form

3 0
3 years ago
Branliest to correct answer explain how you solved it please
nika2105 [10]

Answer:

{1}

Step-by-step explanation:

A ∩ B ∩ C means A intersection B intersection C. That means the question is asking for a set of numbers that are in sets A, B, and C.

{1} is the answer since it is the only number that is in all three sets.

4 0
3 years ago
Awnser please please
astraxan [27]
They're all d).

1) 28>24=10+14

2) Either 96/8=? or 8*?=96 describe the problem, ? being the number of chairs (the blank square in the answers). Of the two only the first appears in the options.

3) This question is ambiguous: if someone went both days, we could say the total number of people who went to the Saturday and Sunday games would be less than 3271+5844=9115. But who wrote the question likely wanted you to just do the sum between the two numbers, so of all options d is likely what they want you to choose.

6 0
3 years ago
A rectangle is 3 cm long and 2 cm wide
Nimfa-mama [501]

Answer:

Perimeter = 100mm

Area = 60mm

Step-by-step explanation:

P= (3x2) + (2x2) =10cm

10mm to 1cm

10cm x 10 = 100mm

A= b x h

= 3 x 2

=6cm

6x10=60mm

7 0
2 years ago
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