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sveticcg [70]
3 years ago
5

What is 6000 minus 3672?

Mathematics
2 answers:
Kamila [148]3 years ago
8 0
6000 - 3672 = 2328

Just use a calculator my friend :)
horsena [70]3 years ago
5 0
I got the same thing 
6000-3672 is 2328 <span />
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I need help with this please!
Korolek [52]

Answer:3/8

Step-by-step explanation:

8 0
3 years ago
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PLEASE ANSWER!!!!!! REALLY IMPORTANT
faust18 [17]

<u>Answer-</u>

<em>The height of the prism is</em><em> 6 units</em>

<u>Solution-</u>

As the base of the prism is a hexagon consisting of 2 congruent isosceles trapezoids.

So,

V_{Prism}=Area_{Base}\times Height

And,

Area_{Base}=2\times \text{Area of the trapezoid}

Also,

\text{Area of the trapezoid}=\dfrac{1}{2}\times \text{Height}\times (\text{Sum of two parallel lines})

=\dfrac{1}{2}\times 3\times (5+8)\\\\=\dfrac{39}{2}

Putting all the values,

V_{Prism}=2\times \dfrac{39}{2}\times Height=39\times Height

As the volume is given, so

\Rightarrow 39\times Height=234

\Rightarrow Height=\dfrac{234}{39}=6

8 0
3 years ago
Read 2 more answers
Which box of crackers is a better deal?
a_sh-v [17]

Answer:

Since each cracker in the 190 gram box costs $ 0.0078 while the 850 gram box costs $ 0.0082 each, the 190 gram box is a better deal.

Step-by-step explanation:

Knowing that a 190-gram box of crackers costs $ 1.49 and an 850-gram box costs $ 6.99, to determine which of them is a better deal, the following calculation must be performed:

1.49 / 190 = 0.0078

6.99 / 850 = 0.0082

Therefore, since each cracker in the 190 gram box costs $ 0.0078 while the 850 gram box costs $ 0.0082 each, the 190 gram box is a better deal.

8 0
3 years ago
The co-ordinate of point P is (x+3) and Q is (x-3). Then find d(P,Q). If coordinate of R is (x+2). Find d(Q,R).
kari74 [83]

Answer:

<h2>d(P, Q) = 6</h2><h2>d(Q, R) = 5</h2>

Step-by-step explanation:

The formula of a distance between two points A(a) and B(b):

<h3>d = |b - a|</h3>

We have P(x + 3), Q(x- 3), R(x + 2).

Substitute:

d(P, Q) = |(x - 3) - (x + 3)| = |x - 3 - x - 3| = |-6| = 6

d(Q, R) = |(x + 2) - (x - 3)| = |x + 2 - x - (-3)| = |2 + 3| = |5| = 5

5 0
3 years ago
Which of shakina's statements regarding acceleration and velocity is false? "when the acceleration is negative, the velocity can
Mekhanik [1.2K]
Let's start by imagining a rock being thrown to the air.
Let's say that going up is the positive direction and so, going down is the negative.
The acceleration is pointing down (because of gravity) so it's always negative. While the rock is going up, it's velocity/speed is positive, but the acceleration is negative.
While the rock is going down, both acceleration and speed are negative.
This shows that the first statemente is true, but the second is false.
You can also think that if you define going DOWN as the POSITIVE direction, you can have both positive acceleration and speed, or positive acceleration and negative speed.
7 0
3 years ago
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