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3 years ago

Which is the correct cofunction identity for tan theta?

Mathematics

1 answer:

Alinara [238K]3 years ago

3 0

The cofunction identities for tangent are:

tan (90° – θ) = cot θ and cot (90° – θ) = tan θ

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Given: 3x < 3.

mamaluj [8]

<span>Divide by 3 and get x<1, so the answer is {x | x < 1}

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3 years ago

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Suppose the linear regression line y=2.1x+130 predicts sales based on the money spent on advertising. If x represents the dollar

slega [8]

Linear regression line y=2.1x+130 predicts sales based on the money spent on advertising.

Linear regression represents the relationship between two variables. the value of y depends on the value of x.

x represents the dollars spent in advertising and y represents the company sales in dollars.

We need to find out sales y when $150 spends on advertising.

Plug in 150 for x and find out y

y = 2.1 x + 130

y = 2.1 (150) + 130

y= 445

The company expects $445 in sales

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3 years ago

Scores on a final exam taken by 1200 students have a bell shaped distribution with mean=72 and standard deviation=9

SVETLANKA909090 [29]

Answer:

a. 72

b. 816

c. 570

d. 30

Step-by-step explanation:

Given the graph is a bell - shaped curve. So, we understand that this is a normal distribution and that the bell - shaped curve is a symmetric curve.

Please refer the figure for a better understanding.

a. In a normal distribution, Mean = Median = Mode

Therefore, Median = Mean = 72

b. We have to know that 68% of the values are within the first standard deviation of the mean.

i.e., 68% values are between Mean $\pm$ Standard Deviation (SD).

Scores between 63 and 81 :

Note that 72 - 9 = 63 and

72 + 9 = 81

This implies scores between 63 and 81 constitute 68% of the values, 34% each, since the curve is symmetric.

Now, Scores between 63 and 81 = $\frac{68}{100} \times 1200$

= 68 X 12 = 816.

That means 816 students have scored between 63 and 81.

c. We have to know that 95% of the values lie between second Standard Deviation of the mean.

i.e., 95% values are between Mean $\pm$ 2(SD).

Note that 90 = 72 + 2(9) = 72 + 18

Also, 54 = 63 - 18.

Scores between 54 and 90 totally constitute 95% of the values. So, Scores between 72 and 90 should amount to $\frac{95}{2} \%$ of the values.

Therefore, Scores between 72 and 90 = $\frac{95}{2(100)} \times 1200 = \frac{95}{200} \times 1200$

$\implies 95 \times 12$ = 570.

That is a total of 570 students scored between 72 and 90.

d. We have to know that 5 % of the values lie on the thirst standard Deviation of the mean.

In this case, 5 % of the values lie between below 54 and above 90.

Since, we are asked to find scores below 54. It should be 2.5% of the values.

So, Scores below 54 = $\frac{2.5}{100} \times 1200$

= 2.5 X 12 = 30.

That is, 30 students have scored below 54.

8 0

2 years ago

Lee wants to cut this piece of canvas into two rectangles that are 3×2 and 3×5. He wants the sum of the areas of the two small r

scoray [572]

First find the area of the large rectangle which is 90 by you times 3 and 3 which is 9 then you times 5 and 2 which is 10 after that u times 9 and 10 which is 90 So to make the small rectangle times 6 and 15 because 3 times 2 equals 6 and 5 times 3 equals 10 so that means the area of one small rectangle is 6 and the other rectangle us 15 then u multiple

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2 years ago

Hmmmmmmmmmmmmmmmmmmmmmmmmmmmmm?

Vesnalui [34]

Answer:

3 is the initial value is just the beginning or the starting number

Step-by-step explanation:

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3 years ago

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