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3 years ago

If the sides of your equilateral triangle are each 3 inches and you are wanting to scale to the larger triangle then...

1 answer:

7 0

Not quite sure what you mean but if you want to multiply a fraction by a whole number you can turn the whole number into a fraction by just putting a one under it.

1/2*5=1/2*5/1

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What would happen if you subtracted a negative ? example 4-(-5)

harkovskaia [24]

Then the two negatives would combine to create a positive.

8 0

2 years ago

Read 2 more answers

PLEASE HELPPPP!!!!!!!!!!

AfilCa [17]

Answer:

y = 2x/3 +6

Step-by-step explanation:

using the formula y=mx+b .........where m is the slope, b is the is the point, where the line intersects the y axis

y = 2/3 x + 6

6 0

2 years ago

Can someone help me will mark brainliest!

lions [1.4K]

Answer:

C. gas prices are decreasing on the interval (2,4) and increasing on the interval (4,6)

Step-by-step explanation:

This means that between the first and fourth day of the week, gas prices drop. This is the opposite for days 5 - 7.

If this answer is correct, please make me Brainliest!

5 0

3 years ago

please i need help lol The amount of clay students used for their last art project is weighed. The line plot displays the amount

Schach [20]

Answer:

2 1/4

Step-by-step explanation:

We need to see how much clay they used if each person in that group used 3/4 clay. There are 4 people in the group.

=> 3/4 x 4 = 12/4 = 3

Now, we need to see how much clay they used if each person in that group used 1/4 clay. There are 3 people in the group

=> 1/4 x 3 = 3/4

Now, we need to see how much more clay was used.

=>3 - 3/4

=> 3/1 - 3/4

=> Take the LCM of the denominators and make the denominators equal.

=> 12/4 - 3/4

=> 9/4

They used 9/4 more clay.

Since there are no options with 9/4, we need to make this improper fraction into a proper fraction.

=> 9/4 = 2 1/4

They used 2 1/4 more clay.

3 0

2 years ago

How do I get (tan^2(x)-sin^2(x))/tan(x) equal to (sin^2(x))/cot(x)

shepuryov [24]

$LHS\\ \\ =\frac { \tan ^{ 2 }{ x-\sin ^{ 2 }{ x } } }{ \tan { x } } \\ \\ =\frac { 1 }{ \tan { x } } \left( \tan ^{ 2 }{ x-\sin ^{ 2 }{ x } } \right)$

$\\ \\ =\frac { \cos { x } }{ \sin { x } } \left( \frac { \sin ^{ 2 }{ x } }{ \cos ^{ 2 }{ x } } -\frac { \sin ^{ 2 }{ x\cos ^{ 2 }{ x } } }{ \cos ^{ 2 }{ x } } \right) \\ \\ =\frac { \cos { x } }{ \sin { x } } \left( \frac { \sin ^{ 2 }{ x-\sin ^{ 2 }{ x\cos ^{ 2 }{ x } } } }{ \cos ^{ 2 }{ x } } \right)$

$\\ \\ =\frac { \cos { x } }{ \sin { x } } \cdot \frac { \sin ^{ 2 }{ x\left( 1-\cos ^{ 2 }{ x } \right) } }{ \cos ^{ 2 }{ x } } \\ \\ =\frac { \cos { x } }{ \sin { x } } \cdot \frac { \sin ^{ 2 }{ x\cdot \sin ^{ 2 }{ x } } }{ \cos ^{ 2 }{ x } } \\ \\ =\frac { \cos { x } \sin ^{ 4 }{ x } }{ \sin { x\cos ^{ 2 }{ x } } } \\ \\ =\frac { \sin ^{ 3 }{ x } }{ \cos { x } }$

$\\ \\ =\sin ^{ 2 }{ x } \cdot \frac { \sin { x } }{ \cos { x } } \\ \\ =\sin ^{ 2 }{ x } \cdot \frac { 1 }{ \frac { \cos { x } }{ \sin { x } } } \\ \\ =\sin ^{ 2 }{ x } \cdot \frac { 1 }{ \cot { x } } \\ \\ =\frac { \sin ^{ 2 }{ x } }{ \cot { x } } \\ \\ =RHS$

8 0

2 years ago