Answer:
The probability of missing both two-point conversion attempts is 7.5%
Step-by-step explanation:
We are informed that the probability of missing the first attempt is 50% of the time. Furthermore, the probability of missing on the second attempt given that he missed the first attempt is 15% of the time
Now,the probability of missing on both the two-point conversion attempts will simply be given by the product of these two probabilities since the events are independent;
50%*15% = 0.5 * 0.15 = 7.5%
Therefore, the probability of missing both two-point conversion attempts is 7.5%
Answer:
S.I= 640
Step-by-step explanation:
I=prt
where p= $8,000
and r= 4%
and t= 2 years
$8,000×4%×2
8,000×4/100×2
80×4×2
=640
Therefore The S.I = 640.
Answer:
Step-by-step explanation:
X= 12
Answer:
2.542
Step-by-step explanation:
Given the data :
Customer Pre-training Survey, x1 __Post-training Survey, x2 __ difference, d = (x2-x1)
A 6 8 2
B 5 5 0
C 10 10 0
D 7 10 3
E 6 8 2
F 5 6 1
G 2 8 6
This is a paired test as each subject has two different data values :
Difference in score, d :
dbar = Σd / n
dbar = (2+0+0+3+2+1+6) /
dbar = 14 / 7
dbar = 2
Standard deviation of d ; Sd = √[Σ(d - dbar)²/n-1]
Using calculator ; Sd = 2.082
Test statistic = dbar ÷ (Sd/√n)
Test statistic = 2 ÷ (2.082 / 7)
Test statistic = 2 ÷ 0.7869220
The statistic = 2.5415
add Them all together and divide by the largest
Step-by-step explanation:hope it helps
