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denis23 [38]
3 years ago
6

10cm+blank equals 100cm

Mathematics
1 answer:
sveticcg [70]3 years ago
6 0
90 cm 
10+90
equals 100
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The angle of depression from a helicopter to a landing pad is 37 degrees. if the helicopter is 1250 feet from the ground. what i
djyliett [7]

The horizontal distance from the helicopter to the landing pad is 1658.81 feet

<em><u>Solution:</u></em>

The figure is attached below

Triangle ABC is a rightangled triangle

A helicopter is flying at point A and landing pad is at point c

Angle of depression of the helicopter is 37 degrees so angle of elevation of this helicopter from landing pad will be same as 37 degrees

The helicopter is 1250 feet from the ground

Therefore, AB = 1250 feet

To find: horizontal distance from the helicopter to the landing pad

BC is the horizontal distance from the helicopter to the landing pad

BC = ?

By the definition of tan,

tan \theta = \frac{opposite}{adjacent}

tan 37 = \frac{AB}{BC}\\\\tan 37 = \frac{1250}{BC}\\\\ 0.75355 = \frac{1250}{BC}\\\\BC = \frac{1250}{0.75355}\\\\BC = 1658.81

Thus the horizontal distance from the helicopter to the landing pad is 1658.81 feet

5 0
3 years ago
Which out of the 2 choices is correct ?
tiny-mole [99]

Answer:

sinB is correct

Step-by-step explanation:

Calculating each of cos/ sin for ∠B

cosB = \frac{adjacent}{hypotenuse} = \frac{6}{3\sqrt{5} } = \frac{2}{\sqrt{5} } and

\frac{2}{\sqrt{5} } × \frac{\sqrt{5} }{\sqrt{5} } = \frac{2\sqrt{5} }{5} ≠ \frac{\sqrt{5} }{5}

--------------------------------------------------------------------------------

sinB = \frac{opposite}{hypotenuse} = \frac{3}{3\sqrt{5} } = \frac{1}{\sqrt{5} } and

\frac{1}{\sqrt{5} } × \frac{\sqrt{5} }{\sqrt{5} } = \frac{\sqrt{5} }{5}

7 0
3 years ago
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