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Akimi4 [234]
3 years ago
8

You and your friend peter are putting new shingles on a roof pitched at 25 degrees. you are sitting on the very top of the roof

when Peter who is at the edge of the roof directly below you, 5.0m away, asks you for a box of nails. Rather than carry the 2.5kg box of nails down to peter, you decide to give the box a push and have it slide down to him. If the coefficient of the kinetic friction between the box and the roof is 0.55, with what speed should you push the box to have it gently come to rest right at the edge of the roof?
Physics
1 answer:
Anna11 [10]3 years ago
6 0

Answer:2.72 m/s

Explanation:

Given

Inclination of shingles\theta =25^{\circ}

Length of inclined Plane s=5 m

coefficient of kinetic friction \mu _k=0.55

Let u be the initial velocity

F_{net}=mg\sin \theta -f_r

F_{net}=mg\sin \theta -\mu mg\cos \theta

a_{net}=\frac{F_{net}}{m}

a_{net}=g\sin \theta -\mu g\cos \theta

a_{net}=4.141-4.884

a_{net}=-0.744 m/s^2 i.e. deceleration

v^2-u^2=2a_{net}s

0-u^2=2\times (-0.744)\cdot 5

u=\sqrt{7.439}

u=2.72 m/s

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Fed [463]

Answer:

B. Decrease the plane’s speed and height

Explanation:

Decrease in speed of plane:

When the speed of the plane is decreased then initial velocity of the package will be lesser. As a result, final velocity will also be lesser because in this case final velocity depends upon the initial velocity.

Decrease in height:

According to law of conservation of energy:

Loss in potential energy = Gain in Kinetic energy  

                                 mgh = ½ mV^2

It means with the decrease in height less potential energy will be converted to kinetic energy. As package has constant mass so it will gain less velocity.

7 0
4 years ago
A tightly closed, well-insulated vacuum flask is an example of which type of<br> system?
nignag [31]

Answer:

Isolated

Explanation:

4 0
4 years ago
Darna rolls the 7.05-kg ball down the lane and it hits the 1.52-kg pin head on. The ball was moving at 8.24 m/s before the colli
Amiraneli [1.4K]

Answer:

The velocity of the ball after the collision is 5.39 m/s

Explanation:

Hi there!

To solve this problem, we will use the conservation of momentum: the momentum of the system ball-pin remains the same before and after the collision. The momentum of the system is calculated as follows:

momentum before the collision (initial momentum) = mb · vb1 + mp · vp1

momentum after the collision (final momentum) = mb · vb2 + mp · vp2

Where:

mb = mass of the ball = 7.05 kg

vb1 = velocity of the ball before the collision = 8.24 m/s

mp = mass of the pin = 1.52 kg

vp1 = velocity of the pin before the collision = 0 m/s.

vb2 = velocity of the ball after the collsion = unknown.

vp2 = velocity of the pin after the collision = 13.2 m/s

Since momentum is conserved, then:

initial momentum = final momentum

mb · vb1 + mp · vp1 = mb · vb2 + mp · vp2

Solving for vb2:

mb · vb1 + mp · vp1 -  mp · vp2 = mb · vb2

(mb · vb1 + mp · vp1 -  mp · vp2) / mb = vb2

Since the pin is initially at rest, vp1 = 0:

(mb · vb1  -  mp · vp2) / mb = vb2

(7.05 kg · 8.24 m/s - 1.52 kg · 13.2 m/s) / 7.05 kg = vb2

vb2 = 5.39 m/s

The velocity of the ball after the collision is 5.39 m/s

4 0
3 years ago
Convert one mean solar day into second​
Naya [18.7K]

Answer:

86400 seconds

Explanation:

To convert a mean solar day to second :

Number of hours in a solar day = 24 hours

Number of minutes per hour = 60 minutes

Number of seconds per minute = 60 minutes

Hence, the number of seconds in a solar day is :

(Number of hours in a solar day * number of minutes in an hour * number of seconds in a minute)

(24 * 60 * 60) seconds = 86400 seconds

Hence, 1 mean solar day = 86400 seconds

3 0
3 years ago
. An aeroplane takes 30 min to travel from Biratnagar to Kathmandu. If the air distance between
Nadya [2.5K]

<u>Answer:</u>

average velocity = \bf 900 \space\ km/h

<u>Explanation:</u>

We can find the average velocity using the following equation:

\boxed{average \space\ velocity = \frac{total \space\ distance  \space\  travelled}{ \space\ time  \space\ taken}} .

In this case:

• total distance travelled = 450 km

• time taken = 30 min = 0.5 h

Substituting these values into the equation:

average \space\ velocity = \frac{450 \space\ km }{ 0.5 \space\ h}

                          ⇒ \bf 900 \space\ km/h

8 0
2 years ago
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