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Ganezh [65]
2 years ago
11

A player prefers to make high passes that lift the puck above the ice. Which stick should the

Physics
1 answer:
Arte-miy333 [17]2 years ago
8 0

Answer:

i dont know

Explanation:

hello

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What is the value of the boltzmann constant of 1.7 moles of gas at 290 K that has an average kinetic energy of 1.4 MJ? A. 7x10^-
fredd [130]

Answer:

The value of  of the Boltzmann constant is 3.14\times 10^{-23} J/K.

Explanation:

Generally the formula for average kinetic energy of a molecule :

K.E=\frac{3}{2}kT

where,

k = Boltzmann’s constant

T = temperature = 290 K

Given:

Number of molecules in 1.7 moles:

1.7\times 6.022\times 10^{23} molecules=1.0237\times 10^{24} molecules

Average kinetic energy of 1.7 moles = 1.4 MJ =1.4\times 10^6 J

Average kinetic energy of 1 molecule = \frac{1.4\times 10^6 J}{1.023\times 10^{24}} =1.3675\times 10^{-18} J

1.3675\times 10^{-18} J=\frac{3}{2}\times k\times (290K)

k=3.14\times 10^{-23} J/K

8 0
3 years ago
A charged isolated metal sphere of diameter 15 cm has a potential of 8500 V relative to V = 0 at infinity. Calculate the energy
Elan Coil [88]

Answer:

u = 0.057 J/m^3

Explanation:

Energy density near the surface of the sphere is given by the formula

u = \frac{1}{2}\epsilon_0 E^2

also for sphere surface we know that

E = \frac{V}{R}

R = radius of sphere

V = potential of the surface

now we have

u = \frac{1}{2}\epsilon_0 (\frac{V^2}{R^2})

now from the above formula we have

u = \frac{1}{2}(8.85 \times 10^{-12})(\frac{8500^2}{0.075^2})

u = 0.057 J/m^3

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range:u²sin2¢/g
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