1. There are 1,200 students at Woodland Hills Elementary. Approximately 600 of

Mathematics

1 answer:

fenix001 [56]2 years ago

4 0

1,200 divide by 600 = 2 students

2 students multiply by 50% is 100 students.

So, approximately 100 students ride their bicycles home.

(If not correctly, I am truly sorry)

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A baseball diamond is a square with side 90 ft. A batter hits the ball and runs toward first base with a speed of 31 ft/s. (a) A

Afina-wow [57]

Answer:

13.86 ft/sec

Step-by-step explanation:

If we let x = distance batter has run at time t and D = distance from second base to the batter at time t, then we know $\frac{dx}{dt}=31 ft/s$ and we want $\frac{dD}{dt}$ when he is halfway (at x = 45).

Using Pythagoras theorem

$D^2=90^2+(90-x)^2\\\text{Differentiating with respect to t}\\2D\frac{dD}{dt}=0+2(90-x)(-1)\frac{dx}{dt}\\2D\frac{dD}{dt}=-2(90-x)\frac{dx}{dt}$

When x=45

$D^2=90^2+(90-x)^2\\D^2=90^2+(90-45)^2\\D^2=10125\\D=\sqrt{10125}$

$2D\frac{dD}{dt}=-2(90-x)\frac{dx}{dt}\\2\sqrt{10125}\frac{dD}{dt}=-2(90-45)(31)\\\frac{dD}{dt}=\frac{-2(45)(31)}{2\sqrt{10125}} =-13.86ft/s$

Thus, when the batter is halfway to first base, the distance between second base and the batter is decreasing at the rate of about 13.86 ft/sec.

4 0

2 years ago

PLEASE PLEASE HELP!! Sketch a triangle and label correctly. Work must be shown for this problem. Round answers to the nearest hu

torisob [31]

Answer:

Please see attached image for the sketch with the labels.

Length "x" of the ramp = 11.70 ft

Step-by-step explanation:

Notice that the geometry to represent the ramp is a right angle triangle, for which we know one of its acute angles ( $20^o$ ), and the size of the side opposite to it (4 ft). Our unknown is the hypotenuse "x" of this right angle triangle, which is the actual ramp length we need to find.

For this, we use the the "sin" function of an angle in the triangle, which is defined as the quotient between the side opposite to the angle, divided by the hypotenuse, and then solve for the unknown "x" in the equation:

$sin(20^o)=\frac{opposite}{hypotenuse}\\ sin(20^o)=\frac{4}{x} \\x=\frac{4}{sin(20^o)} \\x=11.695\,\,ft$