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alexandr1967 [171]
3 years ago
14

Amy and Alex are making models for their science project. Both the models are in the shape of a square pyramid. The

Mathematics
2 answers:
Varvara68 [4.7K]3 years ago
6 0

Answer:

128/3 cubic inches

Step-by-step explanation:

The formula for pyramid volume is (1/3)lwh. Using this we can calculate that the volume of each shape is 320/3 cubic inches and 192/3 inches. When these are subtracted, it reads 128/3 cubic inches.

Ksivusya [100]3 years ago
5 0

Answer:

The answer is 42.67 cubic inches.

Step-by-step explanation:

Both the models are in the shape of a square pyramid.

The length of the sides of the base for both the models is 8 inches.

Amy’s model is 5 inches tall and Alex’s model is 3 inches tall.

The volume is given by :

a^{2}\frac{h}{3}

So, Amy's figure volume is :

8^{2}\times \frac{5}{3} = 106.67 cubic inches

And Alex's figure volume is:

8^{2}\times \frac{3}{3} = 64 cubic inches

So, the difference between volumes is = 106.66-64=42.67 cubic inches.

The answer is 42.67 cubic inches.

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Answer:

Step-by-step explanation:

x - 4y = 4

-4y = -x + 4

y = 1/4x - 1

y + 1 = 1/4(x + 8)

y + 1 = 1/4x + 2

y = 1/4x + 1

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2 years ago
Suppose the scores on a test given to all juniors in a school district are normally distributed with a mean of 74 and a standard
ivann1987 [24]

Answer:

\mu -\sigma = 66 , \mu +\sigma = 82

\mu -2\sigma = 58 , \mu +2\sigma = 90

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And in the figure attached we see the limits with the percentages associated.

Step-by-step explanation:

For this case we know that the random variable of interest is the scores on a test given to all juniors in a school district follows a normal distribution with the following parameters:

X \sim N(\mu= 74, \sigma =8)

For this case we know from the empirical rule that within one deviation from the mean we have approximately 68.2% of the data, within 2 deviations from the mean we have 95% and within 3 deviation 99.7%

We can find the limits and we got:

\mu -\sigma = 66 , \mu +\sigma = 82

\mu -2\sigma = 58 , \mu +2\sigma = 90

\mu -3\sigma = 50 , \mu +3\sigma = 98

And in the figure attached we see the limits with the percentages associated.

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