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3 years ago

If you could please summarise the information in the two screenshots I'll give you brainiest

Chemistry

1 answer:

aleksley [76]3 years ago

4 0

Answer:

Explanation:

A 'mole' is the mass of substance that contains 1 Avogadro's Number of particles of that substance. This is equal to 1 formula weight of the substance. That is when thinking 'moles', think 'how many formula weights are there in the given mass?'

Example.

Given 100 grams of water (H₂O => formula weight = 18 grams/mole) ...

Ask 'how many 18's are there in 100?' => number of moles of H₂O... => 100/18 = 5.555... moles H₂O

This is the same for any substance => how many formula weights are there in the GIVEN mass? Always => #moles.

moles = mass(g)/formula wt(g·mol⁻¹)

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Zinc reacts with excess hydrochloric acid to produce zinc chloride and hydrogen gas. What happens to the reaction rate if you in

agasfer [191]

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3 years ago

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Calculate a reasonable amount (mass in g) of your unknown acid to use for a titration. You will want about 30 mL of titrant to g

Vinil7 [7]

Answer:

"0.60 g" is the appropriate solution.

Explanation:

The given values are:

Volume of base,

= 30 ml

Molarity of base,

= 0.05 m

Molar mass of acid,

= 400 g/mol

As we know,

⇒ $Molarity=\frac{Number \ of \ moles \ of \ base}{Number \ of \ solution}$

On substituting the values, we get

⇒ $0.05=\frac{Number \ of \ moles \ of \ base}{30\times 10^{-3}}$

⇒ $Number \ of \ moles \ of \ base=0.05\times 30\times 10^{-3}$

⇒ $=1.5\times 10^{-3}$

hence,

⇒ $Moles \ of \ acid=\frac{Mass \ of \ acid}{Molar \ mass \ of \ acid}$

On substituting the values, we get

⇒ $1.5\times 10^{-3}=\frac{Mass \ of \ acid}{400}$

⇒ $Mass \ of \ acid=1.5\times 10^{-3}\times 400$

⇒ $=0.60 \ g$

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3 years ago

About 3% of the water on Earth is freshwater. Only about 40% of that freshwater is available for human use. Why is so much fresh

Ilya [14]

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When maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas write the balanved equati

babunello [35]

Answer: When maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas then balanced equation is $MnO_{2} + 4HCl \rightarrow 2H_{2}O + MnCl_{2} + Cl_{2}$ .

Explanation:

The word equation is given as maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas.

Now, in terms of chemical formulae this reaction equation will be as follows.

$MnO_{2} + HCl \rightarrow H_{2}O + MnCl_{2} + Cl_{2}$

Here, number of atoms on reactant side are as follows.

Mn = 1
O = 2
H = 1
Cl = 1

Number of atoms on product side are as follows.

Mn = 1
O = 1
H = 2
Cl = 4

To balance this equation, multiply HCl by 4 on reactant side and multiply $H_{2}O$ by 2 on product side. Therefore, the equation can be rewritten as follows.

$MnO_{2} + 4HCl \rightarrow 2H_{2}O + MnCl_{2} + Cl_{2}$

Hence, number of atoms on reactant side are as follows.

Mn = 1
O = 2
H = 4
Cl = 4

Number of atoms on product side are as follows.

Mn = 1
O = 2
H = 4
Cl = 4

Since, this equation contains same number of atoms on both reactant and product side. Therefore, this equation is now balanced equation.

Thus, we can conclude that when maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas then balanced equation is $MnO_{2} + 4HCl \rightarrow 2H_{2}O + MnCl_{2} + Cl_{2}$ .

6 0

3 years ago