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victus00 [196]
3 years ago
10

If you could please summarise the information in the two screenshots I'll give you brainiest

Chemistry
1 answer:
aleksley [76]3 years ago
4 0

Answer:

Explanation:

A 'mole' is the mass of substance that contains 1 Avogadro's Number of particles of that substance. This is equal to 1 formula weight of the substance. That is when thinking 'moles', think 'how many formula weights are there in the given mass?'

Example.

Given 100 grams of water (H₂O => formula weight = 18 grams/mole) ...

Ask 'how many 18's are there in 100?' => number of moles of H₂O... => 100/18 = 5.555... moles H₂O

This is the same for any substance => how many formula weights are there in the GIVEN mass? Always => #moles.

moles = mass(g)/formula wt(g·mol⁻¹)

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The labeled images each represent the wave patterns found in the electromagnetic wave spectrum. Which image is correctly labeled
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Near Cozumel, Mexico, a scuba diver goes down 60 ft to look at the sea creatures. As she descends, the air pressure increases. W
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Answer: Boyle's Law

Explanation:

Boyle's Law which is also called Mariotte's law was formulated by physicist Robert Boyle in 1662.

It posits that the pressure (p) of a given quantity of gas varies inversely with its volume (v) at constant temperature.

As the Scuba Diver went deeper, the volume of air dropped so the pressure increased.

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5 0
3 years ago
a flask was filled with SO2 at a partial pressure of 0.409 atm and O2 at a partial pressure of 0.601 atm. The following gas-phas
jarptica [38.1K]

Answer:

The equilibrium partial pressure of O2 is 0.545 atm

Explanation:

Step 1: Data given

Partial pressure of SO2 = 0.409 atm

Partial pressure of O2 = 0.601 atm

At equilibrium, the partial pressure of SO2 was 0.297 atm.

Step 2: The balanced equation

2SO2 + O2 ⇆ 2SO3

Step 3: The initial pressure

pSO2 = 0.409 atm

pO2 = 0.601 atm

pSO3 = 0 atm

Step 4: Calculate the pressure at the equilibrium

pSO2 = 0.409 - 2X atm

pO2 = 0.601 - X atm

pSO3 = 2X

pSO2 = 0.409 - 2X atm = 0.297

 X = 0.056 atm

pO2 = 0.601 - 0.056 = 0.545 atm

pSO3 = 2*0.056 = 0.112 atm

Step 5: Calculate Kp

Kp = (pSO3)²/((pO2)*(pSO2)²)

Kp = (0.112²) / (0.545 * 0.297²)

Kp = 0.261

The equilibrium partial pressure of O2 is 0.545 atm

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