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antoniya [11.8K]
3 years ago
14

Check my answer plz!! 100 points. Tell me if they are wrong! 1. You have three elements, A, B, and C, with the following electro

negativity values: A = 0.9 B = 3.0 C = 3.5 You react the elements to form the substances AB, AC, and BC. Answer the following questions:
• What type of substance is AB? What types of bonds are present? Explain your answer.
• What type of substance is AC? What types of bonds are present? Explain your answer.
• What type of substance is BC? What types of bonds are present? Explain your answer.
• If any of the substances are ionic compounds, which element is the cation and which is the anion? Explain your answer.
Answer:
AB is an ionic compound. The electronegativity is different between A and B is greater.
AC is an ionic compound. The electronegativity is different between A and C is greater.
BC is a covalent compound because the electronegativity difference between A and B is small.
AB and AC is an ionic compound. A is the cation and B and C are the anion because the element with lower electronegativity is a cation and the element with the higher electronegativity is an anion making A the cation and B and C an anion.
Your Score ___ of 5
Chemistry
2 answers:
Colt1911 [192]3 years ago
8 0

You have a typo in your answer about BC - it is a covalent compound because the electronegativity difference between B and C is small.


Artyom0805 [142]3 years ago
6 0

look good w small changes below:

Answer:  


AB is an ionic compound. The electronegativity difference between A and B is greater.  


AC is an ionic compound. The electronegativity difference between A and C is greater.  


BC is a covalent compound because the electronegativity difference between C and B is small.


everything else look good!

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Answer:

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What is the volume in liters of 321 g of liquid with a density of 0.84 g/mL
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Density is weight by volume.   

First.  If you divide the weight by density you can find the volume

Second you must convert the ML in to Liters.

\frac{321 \frac{g}{1}}{0.84 \frac{g}{mL}} = \frac{321(g)(mL)}{0.84g}=\frac{321mL}{0.84}=382.14mL

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\frac{1L}{1000mL}

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4 0
3 years ago
20 mL of 80°C water is mixed with 20 mL of 0°C water in a perfect calorimeter. What is the final temperature?
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We can cancel m assuming the two systems are equal in mass. Also, we cancel C since they are the same system. This leaves us,

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Explanation:

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3 0
3 years ago
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