Question

Check my answer plz!! 100 points. Tell me if they are wrong! 1. You have three elements, A, B, and C, with the following electronegativity values: A = 0.9 B = 3.0 C = 3.5 You react the elements to form the substances AB, AC, and BC. Answer the following questions:
• What type of substance is AB? What types of bonds are present? Explain your answer.
• What type of substance is AC? What types of bonds are present? Explain your answer.
• What type of substance is BC? What types of bonds are present? Explain your answer.
• If any of the substances are ionic compounds, which element is the cation and which is the anion? Explain your answer.
Answer:
AB is an ionic compound. The electronegativity is different between A and B is greater.
AC is an ionic compound. The electronegativity is different between A and C is greater.
BC is a covalent compound because the electronegativity difference between A and B is small.
AB and AC is an ionic compound. A is the cation and B and C are the anion because the element with lower electronegativity is a cation and the element with the higher electronegativity is an anion making A the cation and B and C an anion.
Your Score ___ of 5

Answer 1

You have a typo in your answer about BC - it is a covalent compound because the electronegativity difference between B and C is small.

Answer 2

look good w small changes below:

Answer:  

AB is an ionic compound. The electronegativity difference between A and B is greater.  

AC is an ionic compound. The electronegativity difference between A and C is greater.  

BC is a covalent compound because the electronegativity difference between C and B is small.

everything else look good!