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Ksivusya [100]
3 years ago
7

A copper wire is made of copper (Cu) atoms. Which of the following best describes the copper atoms?

Chemistry
2 answers:
Maslowich3 years ago
4 0

Answer: They are all basically the same, but the number of neutrons could vary.

Explanation: The atoms of an element are basically alike. However, atoms of the same element can have different numbers of neutrons and electrons. The number of protons is always the same for atoms of the same element.

Evgesh-ka [11]3 years ago
3 0

Answer: Option (A) is the correct answer.

Explanation:

An element is defined as a substance that contains atoms of same type.

As copper wire is a substance that is made up of only atoms of copper. And, all these atoms of copper will be the same. Hence, it is an element.

This means that all the atoms of copper will have same number of protons, neutrons and electrons.

Thus, we can conclude that the statement they are all exactly the same best describes the copper atoms.

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What mass of ag2co3 could you produce from 12.7 g agno3 assuming that it is the limiting reagent?
zhenek [66]

10.3 g of  Ag_{2} CO_{3} will produce from 12.7 g AgNO_{3}.

In simple terms, a limiting reagent is a reactant that is completely used up in the reaction. 

It is also referred to as a limiting reactant or limiting agent.

Now, according to the question,

Since it is a limiting reagent, it will react fully. 

The mass of AgCO_{3} that will be produced will be:-

Equivalent mole of AgNO_{3} = Equivalent weight of Ag_{2} CO_{3} = 12.7/169.97 = x*2/274x = 10.3 g. 

Hence, 10.3 g of Ag_{2} CO_{3} will be produced.

It is used to restrict the reaction.

It tells you the estimated amount of compound to be used.

It brings quantitative understanding to chemical reactions.

More information on limiting reagents can be found here :

brainly.com/question/11848702

#SPJ4

7 0
2 years ago
A sample of helium gas at 27.0 °C and 3.60 atm pressure is cooled in the same container to a temperature of -73.0 °C. What is th
trasher [3.6K]

Answer: The new pressure, if volume and amount of gas do not change is 2.40 atm

Explanation:

To calculate the final temperature of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1\text{ and }T_1 are the initial pressure and temperature of the gas.

P_2\text{ and }T_2 are the final pressure and temperature of the gas.

We are given:

P_1=3.60atm\\T_1=27^0C=(27+273)K=300K\\P_2=?\\T_2=-73.0^0C=(273-73)=200K

Putting values in above equation, we get:

\frac{3.60}{300K}=\frac{P_2}{200K}\\\\P_2=2.40atm

Thus the new pressure, if volume and amount of gas do not change is  2.40 atm

5 0
3 years ago
What would happen if I swallowed a mento then drank some coca cola?
Sholpan [36]
Your stomach will bubble lol it might kind of tickle
4 0
3 years ago
Read 2 more answers
Which is the best term to use when describing the energy of position?
Minchanka [31]
Answer: potential.

Chemical energy is the energy provided by a chemical reaction.

Kinetic energy is the energy due to the speed.

Potential energy is the energy due to the position. For example, an object on the top of a mountain, has the possibility to perform work if it falls.

Electromagnetic energy. is propagated by waves: radio waves, infrared radiation, microwaves, etc.
4 0
4 years ago
Read 2 more answers
A 101.2 ml sample of 1.00 m naoh is mixed with 50.6 ml of 1.00 m h2so4 in a large styrofoam coffee cup; the cup is fitted with a
Murrr4er [49]

The enthalpy change of the reaction when sodium hydroxide and sulfuric acid react can be calculated using the mass of solution, temperature change, and specific heat of water.

The balanced chemical equation for the reaction can be represented as,

H_{2}SO_{4}(aq) + 2NaOH (aq) ----> Na_{2}SO_{4}(aq) + 2H_{2}O(l)

Given volume of the solution = 101.2 mL + 50.6 mL = 151.8 mL

Heat of the reaction, q = m C .ΔT

m is mass of the solution = 151.8 mL * \frac{1 g}{1 mL} = 151.8 g

C is the specific heat of solution = 4.18 \frac{J}{g. ^{0}C}

ΔT is the temperature change = 31.50^{0}C - 21.45^{0}C = 10.05^{0}C

q = 151.8 g (4.18 \frac{J}{g ^{0}C})(10.05^{0}C) = 6377 J

Moles of NaOH = 101.2 mL * \frac{1L}{1000 mL}*\frac{1.00 mol}{L} = 0.1012 mol NaOH

Moles of H_{2}SO_{4} = 50.6 mL * \frac{1 L}{1000 mL} * \frac{1.0 mol}{1 L} = 0.0506 mol H_{2}SO_{4}

Enthalpy of the reaction = \frac{6377 J*\frac{1kJ}{1000J}}{0.0506 mol} = 126 kJ/mol

5 0
3 years ago
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