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2 years ago

If 42 grams of carbon in 52 grams of oxygen are used how many grams of CO2 will be produced. I need to show work.

Chemistry

1 answer:

UNO [17]2 years ago

4 0

Answer:

How many moles of oxygen gas are required to make 8.33 moles of carbon dioxide? ... be used to produce 1.99 grams of water. 1.99 mg H2O X. 1mol H2O. 18.0g X ... c. If the reaction produces 5.3 mg of carbon dioxide how many grams of water ... X. 25mol O2. 2mol C8H18. X. 32.0g O2. 1mol O2. = 4.80 x 103g O2. Answer ...

Explanation:

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Enter your answer in the provided box. Oxidation of gaseous ClF by F2 yields liquid ClF3, an important fluorinating agent. Use t

MakcuM [25]

Answer : The value of $\Delta H_{rxn}$ for the reaction is, -135.2 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The formation of $ClF_3$ will be,

$ClF(g)+F_2(g)\rightarrow ClF_3(l)$ $\Delta H_{rxn}=?$

The intermediate balanced chemical reaction will be,

(1) $2ClF(g)+O_2(g)\rightarrow Cl_2O(g)+OF_2(g)$ $\Delta H_1=167.5kJ$

(2) $2F_2(g)+O_2(g)\rightarrow 2OF_2(g)$ $\Delta H_2=-43.5kJ$

(3) $2ClF_3(l)+2O_2(g)\rightarrow Cl_2O(g)+3OF_2(g)$ $\Delta H_3=394.4kJ$

We are dividing the reaction 1, 2 and 3 and reversing reaction 3 and then adding all the equations, we get :

(1) $ClF(g)+\frac{1}{2}O_2(g)\rightarrow \frac{1}{2}Cl_2O(g)+\frac{1}{2}OF_2(g)$ $\Delta H_1=\frac{167.5kJ}{2}=83.75kJ$

(2) $F_2(g)+\frac{1}{2}O_2(g)\rightarrow OF_2(g)$ $\Delta H_2=\frac{-43.5kJ}{2}=-21.75kJ$

(3) $\frac{1}{2}Cl_2O(g)+\frac{3}{2}OF_2(g)\rightarrow ClF_3(l)+O_2(g)$ $\Delta H_3=\frac{-394.4kJ}{2}=-197.2kJ$

The expression for enthalpy of formation of $ClF_3$ will be,

$\Delta H_{rxn}=\Delta H_1+\Delta H_2+\Delta H_3$

$\Delta H_{rxn}=(83.75kJ)+(-21.75kJ)+(-197.2kJ)$

$\Delta H_{rxn}=-135.2kJ$

Therefore, the value of $\Delta H_{rxn}$ for the reaction is, -135.2 kJ

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4 years ago

Nitrogen-fixers are the critical links between ______.

bija089 [108]

Answer:

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3 years ago

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What happens when you shoot a neutron at a uranium-238 atom?

serious [3.7K]

Answer: Scientist shoot a whole bunch of neutrons at uranium-235 atoms. When one neutron hits the nucleus the uranium becomes U-236. When it becomes 236, the uranium atoms wants to spilt apart. After it splits it gives off three neutrons and a lot of energy.

Explanation:

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3 years ago

Which among the following can be attracted by a magnet, why?<br> an iron-<br> a piece of paper

grin007 [14]

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an iron

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2 years ago

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Carbon-carbon bonds form the ""backbone"" of nearly every organic and biological molecule. The average bond energy of the C¬C bo

qwelly [4]

1.17 × 10¹⁵ s⁻¹ is the frequency and the wavelength is 3.43 × 10⁻⁷m of the least energetic photon that can break an average C - C bond.

WHAT IS CARBON BACKBONE ?

The carbon backbone is also called the carbon skeleton. All organic compounds are made up of carbon-carbon bonds, creating a carbon skeleton or backbone in the compounds.

Carbon Skeleton Structure :

The carbon skeleton structures consist of bending lines, periodically other elements are written in as well. The carbon skeleton characteristics that change the overall structure includes:

Length of carbon chain (the longer it is the more zig-zags are drawn).
Shape of the carbon chain (branches, rings, etc. all change the shape of the skeleton).
Location of attached functional groups, they need to be put onto the correct point in the skeleton.
Any double or triple bonds that are present, particularly as triple bonds change the shape of the skeleton.

<h3>What is wavelength?</h3>

Forms of electromagnetic radiation like radio waves, light waves or infrared (heat) waves make characteristic patterns as they travel through space. Each wave has a certain shape and length. The distance between peaks (high points) is called wavelength.

Step 1 :

Here we have to calculate the frequency and wavelength of the least energetic photon that can break an average C - C bond and have to find out in what region of the electromagnetic spectrum is this radiation.

Bond energy of C - C = 347 kJ

It is known that E = hv

⇒ $mu = \frac{E}{h}$

Where, E is the energy = 347kJ

h is the planck's constant = $6.626 * 10^{-34}J.s$

v is the frequency

Now substituting the values, frequency can be calculated as,

⇒ $v = \frac{E}{h} = \frac{347kJ/1kJ * mol/6.022 * 10^{23}}{6.626 * 10^{-34}J.s}$

≈ 8.70 × 10¹⁴ s⁻¹ .

Formula of Wavelength :

$\lambda = \frac{hc}{E}$

Where, λ = wavelength

h = 6.6 × 10⁻³⁴

c = 3 × 10⁸

E = bond energy

Now substituting the values, wavelength can be calculated as,

$\lambda = \frac{hc}{E} = \frac{6.6 * 10^{-34} * 3 * 10^{8} * 6.023 * 10^{23}}{347 * 10^{3}} = \frac{119.255 * 10^{-34} * 10^{31} * 10^{-3}}{347} = 0.343 * 10^{-6} = 3.43*10^{-7} m$

Thus, from the above conclusion we can say that 1.17 × 10¹⁵ s⁻¹ is the frequency and the wavelength is 3.43 × 10⁻⁷ m of the least energetic photon that can break an average C - C bond.

Learn more about the wavelength and frequency here :

brainly.com/question/6297363

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1 year ago