Answer:
The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors
P(X⁻ ≥ 96.3) = 0.0087
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that the mean of the Population = 95
Given that the standard deviation of the Population = 5
Let 'X' be the random variable in a normal distribution
Let X⁻ = 96.3
Given that the size 'n' = 84 monitors
<u><em>Step(ii):-</em></u>
<u><em>The Empirical rule</em></u>
Z = 2.383
The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors
P(X⁻ ≥ 96.3) = P(Z≥2.383)
= 1- P( Z<2.383)
= 1-( 0.5 -+A(2.38))
= 0.5 - A(2.38)
= 0.5 -0.4913
= 0.0087
<u><em>Final answer:-</em></u>
The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors
P(X⁻ ≥ 96.3) = 0.0087
Answer:
Choice 3
Step-by-step explanation:
The reading rate of Sam is 0.75 pages/minute.
i.e 30 pages/40 minutes
The reading rate of Bill is 0.5 pages/minute
The reading rate of Francine is 0.72 pages/minute
The reading rate of Leroy is 0.75 pages/minute which is the same as Sam's.
Answer:
do. you know what the poem states nean please i need help
Step-by-step explanation:
please help me
Answer:
D. 35x+111y
add the X’s together and then add the Y’s!
Answer:
Horizontal shift of 1 unit to the right, a vertical shift upward of 6 units, and a vertical stretch by a factor of 3 ..
Step-by-step explanation:
Given function is:
3[|x-1|+2]
Can also be written as:
3|x-1|+6
As we can see that the -1 is grouped with x which means it is a horizontal shift of 1 unit to the right.
Now, 6 is added to the function and it is not grouped with x which means that there is a vertical shift of 6 units upward.
Lastly, 3 is multiplied with the term containing x which means that there is a vertical stretch of 3 units.
Hence, the correct option is:
Horizontal shift of 1 unit to the right, a vertical shift upward of 6 units, and a vertical stretch by a factor of 3 ..
