Answer:
Explanation:
mass of capsule, m = 210 kg
initial velocity, u = 311 km/h = 86.39 m/s
final velocity, v = 0 m/s
distance of soil penetrated, d = 81 cm = 0.81 m
1.
Let a is the acceleration.
Use third equation in motion.
v² = u² + 2as
0 = 86.39² + 2 x a x 0.81
a = - 4606.9
a = - 4607 m/s²
Thus, the acceleration during the crash is 4607 m/s².
2. g = 9.8 m/s²
a / g = 4607 / 9.8
a = 470 g
Thus, the acceleration is 470 g .
3. Force = m a
F = 210 x 4607
F = 967470 N
Thus, the force is 967470 N.
4. Weight of capsule = m g = 210 x 9.8 = 2058 N
F / mg = 967470 / 2058
F = 470 times the weight of capsule.
5. Let t be the time.
Use first equation of motion.
v = u + at
0 = 86.39 - 4607 x t
t = 0.0188 second