Answer:
The net downward force on the tank is 
Explanation:
Given that,
Area = 1.60 m²
Suppose the design of a cylindrical, pressurized water tank for a future colony on Mars, where the acceleration due to gravity is 3.71 meters per second per second. The pressure at the surface of the water will be 150 K Pa , and the depth of the water will be 14.4 m . The pressure of the air in the building outside the tank will be 88.0 K Pa.
We need to calculate the net downward force on the tank
Using formula of formula

Where, P = pressure
g = gravity at mars
h = height
A = area
Put the value into the formula


Hence, The net downward force on the tank is 
Answer:
New force, 
Explanation:
Given that, two point charges attract each other with an electric force of magnitude F. It is given by :

If one charge is reduced to one-third its original value and the distance between the charges is doubled such that,
, 



So, the electric force between them is reduced to (1/12). Hence, the correct option is (d).
Answer:
75 rotations
Explanation:
f0 = 0, f = 3000 rpm = 50 rps, t = 3 s
(a) use first equation of motion for rotational motion
w = w0 + α t
2 x 3.14 x 50 = 0 + α x 3
α = 104.67 rad/s^2
(b) Let θ be the angular displacement
use second equation of motion for rotational motion
θ = w0 t + 1/2 α t^2
θ = 0 + 0.5 x 104.67 x 3 x 3
θ = 471.015 rad
The angle turn in one rotation is 2 π radian.
Number of rotation = 471.015 / (2 x 3.14) = 75 rotations
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