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Drupady [299]
3 years ago
14

Which of the following is not true about minerals?

Physics
2 answers:
mezya [45]3 years ago
6 0

Answer:

I think it's A but I'm not sure

Nikolay [14]3 years ago
6 0
A the always include oxygen and silicon
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Find the net downward force on the tank's flat bottom, of area 1.60 m2 , exerted by the water and air inside the tank and the ai
Dovator [93]

Answer:

The net downward force on the tank is 1.85\times10^{5}\ N

Explanation:

Given that,

Area = 1.60 m²

Suppose the design of a cylindrical, pressurized water tank for a future colony on Mars, where the acceleration due to gravity is 3.71 meters per second per second. The pressure at the surface of the water will be 150 K Pa , and the depth of the water will be 14.4 m . The pressure of the air in the building outside the tank will be 88.0 K Pa.

We need to calculate the net downward force on the tank

Using formula of formula

F=(P+\rho\times g\times h-P_{out})A

Where, P = pressure

g = gravity at mars

h = height

A = area

Put the value into the formula

F=(150\times10^3+1.00\times10^3\times3.71\times14.4-88.0\times10^{3})\times1.60

F=1.85\times10^{5}\ N

Hence, The net downward force on the tank is 1.85\times10^{5}\ N

8 0
4 years ago
Two point charges attract each other with an electric force of magnitude F. If one charge is reduced to one-third its original v
Pavel [41]

Answer:

New force, F'=\dfrac{F}{12}

Explanation:

Given that, two point charges attract each other with an electric force of magnitude F. It is given by :

F=k\dfrac{q_1q_2}{r^2}

If one charge is reduced to one-third its original value and the distance between the charges is doubled such that,

q_1'=\dfrac{q_1}{3}, r'=2r

F'=k\dfrac{q_1'q_2'}{r'^2}

F'=k\dfrac{(q_1/3)q_2}{(2r)^2}

F'=\dfrac{F}{12}

So, the electric force between them is reduced to (1/12). Hence, the correct option is (d).

3 0
3 years ago
The crankshaft in a race car goes from rest to 3000 rpm in 3.0 s . (a) What is the crankshaft's angular acceleration?
Talja [164]

Answer:

75 rotations

Explanation:

f0 = 0, f = 3000 rpm = 50 rps, t = 3 s

(a) use first equation of motion for rotational motion

w = w0 + α t

2 x 3.14 x 50 = 0 + α x 3

α = 104.67 rad/s^2

(b) Let θ be the angular displacement

use second equation of motion for rotational motion

θ = w0 t + 1/2 α t^2

θ = 0 + 0.5 x 104.67 x 3 x 3

θ = 471.015 rad

The angle turn in one rotation is 2 π radian.

Number of rotation = 471.015 / (2 x 3.14) = 75 rotations

7 0
3 years ago
What activities should you avoid to prevent static discharge while working on a computer?
nordsb [41]
Dont where socks or stand on carpet while working on a computer, also dont set components on carpet.
6 0
3 years ago
What could cause a physical change in a bar of steel
ss7ja [257]
-- a very very very hot oven

-- a very heavy hammer

-- an electric drill
6 0
3 years ago
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