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andreev551 [17]
3 years ago
8

The air exerts a forward force of 10 N on the propeller of a 0.20-kg model airplane. If the plane accelerates forward at 2.0 m/s

2 , what is the magnitude of the resistive force exerted by the air on the airplane
Physics
1 answer:
Dennis_Churaev [7]3 years ago
4 0

Answer:

Explanation:

dndgnbgdn bdvngn nvgn  g ueefeeuefebjf uvdyvjskv

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A ball is thrown into the air with an upward velocity of 32 feet per second. Its height, h, in feet after t
LekaFEV [45]
Differentiate the expression, to obtain expression for velocity. Set velocity to 0, this when max height is reached. Obtain the tmax from that expression.

<span>h(t) = –16t² + 32t + 6
</span><span>h'(t) = –32t² + 32
0 = </span>–32t² + 32
t max= 1

hmax = <span> –16(1)² + 32(1) + 6
hmax = 22

Therefore, first option is the correct answer.</span>
8 0
3 years ago
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4 years ago
Does both the independent variable and the dependent variable affect each other?
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No.  The DEPENDENT variable is the only one that DEPENDS on
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3 0
3 years ago
Johan's race time was 45.03 seconds. Kyle's race time was 0.1 second less than Johan's time. What was Kyle's race time?
frutty [35]
Wouldn’t that just be 44.93 seconds?
6 0
3 years ago
A 2.5g copper penny is given a charge of -4.0*10^-9c. how mny excess electrons are on the penny?
Lyrx [107]

Answer : The excess of electrons on the penny are, 2.5\times 10^{10} electrons

Solution : Given,

Total charge = -4.0\times 10^{-9}C

Charge on electron = -1.6\times 10^{-19}C

Formula used :

\text{Excess of electrons}=\frac{\text{Total charge}}{\text{Charge of electron}}

Now put all the given values in this formula, we get the excess of electrons present on the penny.

\text{Excess of electrons}=\frac{\text{Total charge}}{\text{Charge of electron}}=\frac{-4.0\times 10^{-9}C}{-1.6\times 10^{-19}C/e^-}=2.5\times 10^{10}e^-

Therefore, the excess of electrons on the penny are, 2.5\times 10^{10} electrons


7 0
3 years ago
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