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nikdorinn [45]
3 years ago
5

The pressure, p, of water (in pounds per square foot) at a depth of d feet below the surface is given by the formula p=15+15/33d

. If a diver is 100 feet below surface, what is the pressure of the water on the diver?
a.15.0 pounds per square feet
b.38.63 pounds per square feet
c.1545.45 pounds per square feet
d.60.45 pounds per square feet
Physics
2 answers:
Viefleur [7K]3 years ago
8 0
The pressure of the water on the diver is given in an expression written as:

<span>p=15+15/33d

where p is the pressure and d is the distance of the diver </span><span>below the surface.

The pressure is calculated as follows:

</span>p=15+15/33(100) = 15.00  pounds per square feet

Therefore, the correct answer is option A.
Nadusha1986 [10]3 years ago
6 0

Answer:

CCCCCCCCCCC

Explanation:

The rate of change for the diver is

8.6 − 4.3

20 − 10

= 0.43. Therefore, the rate of change for the submarine is 4(0.43) = 1.72 and p = 1.72d

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An object located near the surface of Earth has a weight of a 245 N
marusya05 [52]

Answer:

The mass of the object is 24.5 kg and weight of the object on Mars is 91.14 N.

Explanation:

Weight of the object on the surface of Earth, W = 245 N

On the surface of Earth, acceleration due to gravity, g = 10 m/s²

Weight of an object is given by :

W = mg

m is mass

m=\dfrac{W}{g}\\\\m=\dfrac{245\ N}{10\ m/s^2}\\\\=24.5\ kg

So, the mass of the object is 24.5 kg

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Weight of the object on Mars,

W' =mg'

W' = 24.5 kg × 3.72 m/s²

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4 0
3 years ago
The force of Earths gravity keeps earth in orbit true or false
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Answer:

<u>True</u><u> </u>

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8 0
3 years ago
If the average velocity during the athlete's walk back
goblinko [34]

Hence ,From the Guide there are other parameters which with this equation will give the exact time the athlete's walk back

T=\frac{d}{1.50}

From the question we are told

If the average velocity during the athlete's walk back  to the starting line in Guided Example 2.5 is – 1.50 m/s,

Generally the equation Time spent  is mathematically given as

T=\frac{d}{v}

Therefore

T=\frac{d}{1.50}

Hence ,From the Guide there are other parameters which with this equation will give the exact time the athlete's walk back

T=\frac{d}{1.50}

For more information on this visit

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How can you produce more power than an excavator?
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Just do energy spent divided by time to get your answer. With this we can say a human might be able to!
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