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LuckyWell [14K]
3 years ago
6

The heat in the house is set to keep the minimum and maximum temperatures (in degrees Fahrenheit) according to the equation |x –

72.5| = 4. What are the minimum and maximum temperatures in the house? 72.5°F and 76.5°F 68.5°F and 76.5°F 70.5°F and 74.5°F 72.5°F and 74.5°F
Mathematics
1 answer:
dmitriy555 [2]3 years ago
5 0
|x-72.5|=4 \\
x-72.5=-4 \ \lor \ x-72.5=4 \\
x=-4+72.5 \ \lor \ x=4+72.5 \\
x=68.5 \ \lor \ x=76.5

The minimum and maximum temperatures in the house are 68.5°F and 76.5°.
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What is/are the classification of functions that has its inverse?
UNO [17]

Answer:

Invertible functions

Step-by-step explanation:

An inverse of a function is one that reverses the operation of the function such that the result of the function on a variable, is reversed back to the initial variable

Therefore, when we have the the result of the function, f on x as y given as follows;

f(x) = y

The inverse of the function, g on the result, y gives the initial variable, x as follows;

g(y) = x

Example of invertible functions includes;

f(x) = x²

An example of a non-invertible function includes;

f(x) = 2·x².

4 0
3 years ago
Please help it’s urgent
katrin2010 [14]

\bold{\text{Answer:}\quad \dfrac{-48x^4-42x^3-15x^2-5x}{(8x+7)(3x+1)}}

<u>Step-by-step explanation:</u>

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5 0
3 years ago
An arched drainage culvert can be modelled by the function:
Zanzabum

Substitute 136.5 for y.

136.5=\frac{x(191-x)}{60}

8190=x(191-x)

8190=191x-x^{2}

x^{2} -191x+8190=0

Compare this equation with ax^{2} +bx+c=0

a = 1, b = - 191, c = 8190

x=\frac{-b+\sqrt{b^{2}-4ac } }{2} or

x=\frac{-b-\sqrt{b^{2}-4ac } }{2}

x=\frac{191+\sqrt{191^{2}-4(1)(8190) } }{2} or

x=\frac{191-\sqrt{191^{2}-4(1)(8190) } }{2}

x=\frac{191+\sqrt{36481-32760 } }{2} or

x=\frac{191-\sqrt{36481-32760 } }{2}

x=\frac{191+\sqrt{3721 } }{2} or

x=\frac{191-\sqrt{3721 } }{2}

x=\frac{191+61}{2} or

x=\frac{191-61}{2}

x=\frac{252}{2} or

x=\frac{130}{2}

x = 126 or x = 65

Hence, the points on the curve are (65, 136.5) and (126, 136.5).

The width of the air space is the distance between these points.

Width = \sqrt{(x_{2}- x_{1})^{2} +( y_{2}- y_{1}) ^{2}

= \sqrt{(126- 65)^{2} +(136.5-136.5) ^{2}

= 126 - 65

= 61

Hence, width of the air space is 61m.



5 0
3 years ago
What's LCD<br> 5/6<br> 3/18<br> 7/9<br> 1/126
Rudiy27

Answer:

126.

Step-by-step explanation:

One way to do this is to see if 126 is divisible by 6,9 and 18. If so then the LCD is 126.

Use your calculator to check.  

It is 126.

8 0
3 years ago
The amount of force needed to keep a 0.1 kg basketball moving at a constant speed of 6 m/s on friction less ice is ____ Newtons
3241004551 [841]
Basketball has a mass of 0.1kg
m = 0.1 kg
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a = 0m/s²
The constant speed is 6m/s
v = 6m/s
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F = ma
F = m × 0
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So, since the basket ball is moving at constant speed, then, the force need to keep the ball moving is 0N.
7 0
3 years ago
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