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2 years ago

Solve for × and then find the missing angle in the triangle below. SHOW ALL WORK.

Mathematics

2 answers:

Sholpan [36]2 years ago

8 0

Answer:

x = 4°

Step-by-step explanation:

all angles in a triangle sum up to 180°

6x + 38° + 5x + 8° + 90° = 180 °

11x +136° = 180°

11x = 44°

x = 4°

JulsSmile [24]2 years ago

3 0

Answer:

The value of x is <u>4</u>.

∠E = 62⁰
∠G = 28⁰
∠O = 90⁰

Step-by-step explanation:

As we know that the sum of interior angles of triangle is 180⁰.

So, adding all the given sides and subtracting to 180⁰, to find the value of x.

$\begin{gathered} \quad{\implies{\sf{Sum\:of\:all\: angles={180}^{\circ}}}}\\\\\quad{\implies{\tt{6x + {38}^{\circ} + {90}^{\circ} +5x + {8}^{\circ} = {180}^{\circ}}}}\\\\\quad{\implies{\tt{(6x + 5x) + ({38}^{\circ} + {90}^{\circ} + {8}^{\circ}) = {180}^{\circ}}}}\\\\\quad{\implies{\tt{(11x) + ({128}^{\circ} + {8}^{\circ}) = {180}^{\circ}}}}\\\\\quad{\implies{\tt{(11x) + ({136}^{\circ}) = {180}^{\circ}}}}\\\\\quad{\implies{\tt{11x + {136}^{\circ} = {180}^{\circ}}}}\\\\\quad{\implies{\tt{11x = {180}^{\circ} - {136}^{ \circ}}}}\\\\\quad{\implies{\tt{11x = {44}^{ \circ}}}}\\\\\quad{\implies{\tt{x = \dfrac{44}{11}}}}\\\\\quad{\implies{\tt{\underline{\underline{x = 4}}}}}\end{gathered}$

Hence, the value of x is 4.

Now, we know the value of x. So, calculating the mission angles of triangle :

➠ ∠E = 6x+38⁰ = 6×4+38 = 62⁰
➠ ∠G = 5x+8⁰ = 5×4+8 = 28⁰
➠ ∠O = 90⁰

$\rule{300}{2.5}$

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Sara has agreed to help with her younger sister's science fair experiment. Her sister planted string beans in two pots. She is

Delvig [45]

Answer: plants are same height in 30 days; Plant A is tallest in 6 weeks

Step-by-step explanation:

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7 0

7 months ago

Which of the following is not one of the 8th roots of unity?

Anika [276]

Answer:

1+i

Step-by-step explanation:

To find the 8th roots of unity, you have to find the trigonometric form of unity.

1. Since $z=1=1+0\cdot i,$ then

$Rez=1,\\ \\Im z=0$

and

$|z|=\sqrt{1^2+0^2}=1,\\ \\\\\cos\varphi =\dfrac{Rez}{|z|}=\dfrac{1}{1}=1,\\ \\\sin\varphi =\dfrac{Imz}{|z|}=\dfrac{0}{1}=0.$

This gives you $\varphi=0.$

Thus,

$z=1\cdot(\cos 0+i\sin 0).$

2. The 8th roots can be calculated using following formula:

$\sqrt[8]{z}=\{\sqrt[8]{|z|} (\cos\dfrac{\varphi+2\pi k}{8}+i\sin \dfrac{\varphi+2\pi k}{8}), k=0,\ 1,\dots,7\}.$

Now

at k=0, $z_0=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 0}{8}+i\sin \dfrac{0+2\pi \cdot 0}{8})=1\cdot (1+0\cdot i)=1;$

at k=1, $z_1=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 1}{8}+i\sin \dfrac{0+2\pi \cdot 1}{8})=1\cdot (\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2})=\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2};$

at k=2, $z_2=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 2}{8}+i\sin \dfrac{0+2\pi \cdot 2}{8})=1\cdot (0+1\cdot i)=i;$

at k=3, $z_3=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 3}{8}+i\sin \dfrac{0+2\pi \cdot 3}{8})=1\cdot (-\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2})=-\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2};$

at k=4, $z_4=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 4}{8}+i\sin \dfrac{0+2\pi \cdot 4}{8})=1\cdot (-1+0\cdot i)=-1;$

at k=5, $z_5=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 5}{8}+i\sin \dfrac{0+2\pi \cdot 5}{8})=1\cdot (-\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2})=-\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2};$

at k=6, $z_6=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 6}{8}+i\sin \dfrac{0+2\pi \cdot 6}{8})=1\cdot (0-1\cdot i)=-i;$

at k=7, $z_7=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 7}{8}+i\sin \dfrac{0+2\pi \cdot 7}{8})=1\cdot (\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2})=\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2};$

The 8th roots are

$\{1,\ \dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2},\ i, -\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2},\ -1, -\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2},\ -i,\ \dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2}\}.$