Is 4/5 x 7/7 greater than or less than 4/5 (help plsss)

Aaron is 5 years younger than Ron. Four years later, Ron will be twice as old as Aaron.

Hunter-Best [27]

Answer:

Aaron’s present age = x - 5 = 6 - 5 = 1

Step-by-step explanation:

Let Ron’s present age be x.

Then Aaron’s present age = x - 5

After 4 years Ron’s age = x + 4, Aaron’s age x - 5 + 4.

According to the question;

Ron will be twice as old as Aaron.

Therefore, x + 4 = 2(x - 5 + 4)

⇒ x + 4 = 2(x - 1)

⇒ x + 4 = 2x - 2

⇒ x - 2x = -2 - 4

⇒ -x = -6

⇒ x = 6

Therefore, Aaron’s present age = x - 5 = 6 - 5 = 1

Hope this answer helps you :)

Have a great day

Mark brainliest

3 0

3 years ago

Mr. Salazar assigns the same number of homework questions each school day. The ratio table below shows the total number of homew

vivado [14]

Answer The Answer is 80

Step-by-step explanation:

4*5=20

8*5=40

11*5=55

so 16*5=80

7 0

3 years ago

Read 2 more answers

Write the following ratio using two other notations. 5/9 Use only the numbers above (not any others).

slava [35]

5:9 and 5 to 9 are two other ways to write the fraction 5/9.

I hope this helps:)

3 0

3 years ago

You had $23 to spend on five raffle tickets. After buying them, you had $8.

Sophie [7]

Answer:3

Step-by-step explanation:

23-8= 15

15/5=3

5 0

3 years ago

Read 2 more answers

Let f be a differentiable function such that f(1)=π and f'(x)=√x^3+6. what is the value of f(5)?

natali 33 [55]

The value of f(5) is 49.1

Step-by-step explanation:

To find f(x) from f'(x) use the integration

f(x) = ∫ f'(x)

1. Find The integration of f'(x) with the constant term

2. Substitute x by 1 and f(x) by π to find the constant term

3. Write the differential function f(x) and substitute x by 5 to find f(5)

∵ f'(x) = $\sqrt{x^{3}}$ + 6

- Change the root to fraction power

∵ $\sqrt{x^{3}}$ = $x^{\frac{3}{2}}$

∴ f'(x) = $x^{\frac{3}{2}}$ + 6

∴ f(x) = ∫ $x^{\frac{3}{2}}$ + 6

- In integration add the power by 1 and divide the coefficient by the

new power and insert x with the constant term

∴ f(x) = $\frac{x^{\frac{5}{2}}}{\frac{5}{2}}$ + 6x + c

- c is the constant of integration

∵ $\frac{x^{\frac{5}{2}}}{\frac{5}{2}}=\frac{2}{5}x^{\frac{5}{2}}$

∴ f(x) = $\frac{2}{5}$ $x^{\frac{5}{2}}$ + 6x + c

- To find c substitute x by 1 and f(x) by π

∴ π = $\frac{2}{5}$ $(1)^{\frac{5}{2}}$ + 6(1) + c

∴ π = $\frac{2}{5}$ + 6 + c

∴ π = 6.4 + c

- Subtract 6.4 from both sides

∴ c = - 3.2584

∴ f(x) = $\frac{2}{5}$ $x^{\frac{5}{2}}$ + 6x - 3.2584

To find f(5) Substitute x by 5

∵ x = 5

∴ f(5) = $\frac{2}{5}$ $(5)^{\frac{5}{2}}$ + 6(5) - 3.2584

∴ f(5) = 49.1

The value of f(5) is 49.1

Learn more:

You can learn more about differentiation in brainly.com/question/4279146

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4 0

3 years ago