Let KLMN be a trapezoid (see added picture). From the point M put down the trapezoid height MP, then quadrilateral KLMP is square and KP=MP=10.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
Area of KLMN is egual to

sq. units.
Answer:
41 2/3 feet
Step-by-step explanation:
The sum of wall lengths (in feet) is ...
(12 1/4) + (10) + (12 1/4) + (10 -2 5/6)
= (12 + 10 + 12 + 8) + (1/4 + 1/4 - 5/6)
= 42 + (3/12 + 3/12 -10/12)
= 42 - 4/12 = 42 - 1/3
= 41 2/3 . . . feet
Answer:
Choice C: 
Step-by-step explanation:
To find your slope do:


that's how you get 1/2
4 is just the y-int.
As I understand from the given above, each box when empty weighs 5-2 kg or 3 kg. To determine the total weight of Michael's boxes when empty, we just have to multiply 3 kg by 5. This gives us an answer of 15 kg. Thus, the total mass of Michael's boxes is 15 kg.
Answer:
pretty good tired of the virus stuff but good
Step-by-step explanation: