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svetoff [14.1K]
3 years ago
14

Y-2x^2=-3 graph of the function?

Mathematics
1 answer:
blsea [12.9K]3 years ago
4 0

Answer:

We cant make graphs on here but if you put the quadiraletal to the right and drag the left numbers toward the front.

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Step-by-step explanation:

The radius r(t)r(t)r, (, t, )of a sphere is increasing at a rate of 7.57.57, point, 5 meters per minute. At a certain instant t_0t 0 ​ t, start subscript, 0, end subscript, the radius is 555 meters. What is the rate of change of the surface area S(t)S(t)S, (, t, )of the sphere at that instant?

If i could understand the question correctly, the typos notwithstanding

r=radius, 555m

dr/dt=rate of change in radius 5m/min

ds/dt=rate of change in surface area   ?

S=area of a sphere 4\pi r^{2}

ds/dt=ds/dr*dr/dt.................................1

ds/dr=differentiation of the area of a sphere=8\pi r

ds/dt=8\pi 555*5

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\bf \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-(-2)=-\cfrac{7}{4}(x-4)&#10;\\\\\\&#10;y+2=-\cfrac{7}{4}(x-4)\implies y+2=-\cfrac{7}{4}x+7\implies y=-\cfrac{7}{4}x+9
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