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Artemon [7]
3 years ago
5

Circle 1 is centwred at (-4, 5) and has a radius of 2 centimeters. Circle 2 is centered at (2, 1) and has a radius of 6 centimet

ers. What transformations can be applied to circle 1 to prove that the circles are similar? The circles are similar because you can translate circle 1 using the transformation rule ( x, x) and then dilate it using a scale factor of ( ).
Mathematics
1 answer:
vichka [17]3 years ago
7 0
The answer would be (6, 4) and then dilate by 3.
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Answer:

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3 years ago
the volume of a cube is increasing at a constant rate of 824 cubic centimeters per minute. At the instant when the volume of the
Maurinko [17]

Answer:

DA/dt  = 75.27 cm²

Step-by-step explanation:

Cube Volume    =   V(c)   =  683  cm³

DV(c) /dt    =  824 cm³

V(c,x) = x³    

Then

DV(c,x)/ dt   =  3x² Dx/dt

( DV(c,x)/ dt )/ 3x²  =  Dx/dt       (1)

Now  as  V(c,x) = x³    when    V(c,x)  =  683 cm³     x = ∛683

x  =  8.806     ( from excel)

And by subtitution of this value in equation (1)

Dx/dt   =  ( DV(c,x)/ dt )/ 3x²   ⇒  Dx/dt  =  824 / 3*x²

  Dx/dt   = 824 /3*77.55

Dx/dt   =  824/232,64

Dx/dt   = 3,542

Then we got  Dx/dt  where x is cube edge. The area of the face is x² then

the rate of change of the suface area is  

DA/dt  = ( Dx/dt )²*6         ( 6 faces of a cube)

DA/dt  = (3.542)²*6

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6 0
3 years ago
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andre [41]
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Ivanshal [37]
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madreJ [45]
Set up a system of equations.
l=4w
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Substitute l in to the second equation.
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Substitute w back into the first equation.
l=4(11)=44

So, the length is 44 feet and the width is 11 feet.

Hope this helped!
8 0
3 years ago
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