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Lena [83]
3 years ago
6

Help me ASAP please :( Type the correct answer in each box. Write your answers as fractions, using / as the fraction bar, and wr

ite the greater value first.

Mathematics
1 answer:
Alla [95]3 years ago
4 0

Answer:

see explanation

Step-by-step explanation:

Using the laws of logarithms

• log x - log y = log(\frac{x}{y})

• log_{b} x = n ⇔ x = b^{n}

Hence

log_{x}( \frac{8x-3}{4} ) = 2, hence

\frac{8x-3}{4} = x² ( multiply both sides by 4 )

8x - 3 = 4x² ← rearrange into standard form

Subtract 8x - 3 from both sides

4x² - 8x  + 3 = 0 ← in standard form

(2x - 1)(2x - 3) = 0 ← in factored form

Equate each factor to zero and solve for x

2x - 1 = 0 ⇒ 2x = 1 ⇒ x = \frac{1}{2}

2x - 3 = 0 ⇒ 2x = 3 ⇒ x = \frac{3}{2}

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Now, when the error was discovered, it is now worth half of the  value previously

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Given:

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defon

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