Answer:
5.5296
Step-by-step explanation:
to evaluate the expression 4x^4 y^3 we would substitute the value of x and y into it and evaluate. since x = 1/5 and y = 6
4x^4 y^3
4 × x^4 × 4× y³
4 × (1/5)∧4 × 4 × 6³
4× (0.2)∧4 × 4 × 216
4 × 0.0016 × 864
0.0064 × 864
5.5296
No solution exists for -3x+y=-18 and -3x+y=-6
Answer:
X = 0.9
Step-by-step explanation:
Assume uniformly accelerated motion
Vf = Vo - at => a= [Vo - Vf] / t
Vf = 0, t = 20 s => a = Vo / 20
x = Vot - at^2 / 2
x = Vot - (Vo / 20) * t^2 /2
x = 1775 feet * [1 mile / 5280 feet] = 0.336 mile
t = 20 s
=> 0.336 = 20Vo - Vo(20)^2 /(40) = 20Vo - 10 Vo = 10 Vo
=> Vo = 0.336 /10 = 0.0336 mile /s
Vo = 0.0336 mile/s * 3600 s/h = 120.96 mile / h
Therefore, the car was way over the speed limit.
