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2 years ago

What is the equation of the line, in slope-intercept form, that passes through (3, -1) and (-1, 5)?

Mathematics

2 answers:

Delicious77 [7]2 years ago

7 0

Answer:a

Step-by-step explanation:

Valentin [98]2 years ago

4 0

Answer: a) y = - 3/2 x + 7/2

Step-by-step explanation:

The equation of a straight line can be represented in the slope-intercept form, y = mx + c

Where c = y intercept

m represents the slope of the line.

m = (y2 - y1)/(x2 - x1)

y2 = final value of y

y 1 = initial value of y

x2 = final value of x

x1 = initial value of x

The line passes through (3, - 1) and (- 1, 5),

y2 = 5

y1 = -1

x2 = - 1

x1 = 3

Slope,m = (5 - - 1)/(- 1 - 3) = 6/- 4 =

- 3/2

To determine the y intercept, we would substitute x = 3, y = - 1 and m= - 3/2 into y = mx + c. It becomes

- 1 = - 3/2 × 3 + c

- 1 = - 9/2 + c

c = - 1 + 9/2

c = 7/2

The equation becomes

y = - 3x/2 + 7/2

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Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega

AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

To find the simplified form of the given expression :

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

$=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2$ ( using the property $(ab)^m=a^m.b^m$ )

$=(2^6)(3^{-12})\times (2^{-6})(3^4)$ ( using the property $(a^m)^n=a^{mn}$

$=(2^6)(2^{-6})(3^{-12})(3^4)$ ( combining the like powers )

$=2^{6-6}3^{-12+4}$ ( using the property $a^m.a^n=a^{m+n}$ )

$=2^03^{-8}$

$=\frac{1}{3^8}$ ( using the property $a^{-m}=\frac{1}{a^m}$ )

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

6 0

3 years ago

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-2=___+6<br> Fill in the blank!

Drupady [299]

Answer:

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Step-by-step explanation:

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2 years ago

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7(2a−9)−(8a+2) Simplified please anyone?

Verizon [17]

Answer:

6a+61

Step-by-step explanation:

7(2a-9)-(8a+2)

7x2a=14a

7x9=63

14a+63-(8a+2)

-1x8a=-8a

-1x2=-2

14a+63-8a-2

6a+61

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3 years ago

A basket of fruit holds 12 apples, 24 pears, and 16 oranges. Find the ratio of apples, pears, and oranges in the basket.

miv72 [106K]

Answer:

3:6:4

Step-by-step explanation:

We are given that

Number of apples in the basket=12

Number of pears in the basket=24

Number of oranges in the basket=16

We have to find the ratio of apples, pears and oranges in the basket.

$12=4\times 3$

$24=4\times 3\times 2$

$16=4\times 2\times 2$

HCF (12,24,16)=4

Now, divide each number by HCF

Then, we get

3:6:4

Therefore, the ratio of apples, pears and oranges in the basket.

3:6:4

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2 years ago

Which transformations could have occurred to map ABC to A"B"C?

Bess [88]

Answer:

Reflection and a Dilation (I'm not too sure if this is correct hopefully it helps)

Step-by-step explanation:

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2 years ago

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