Triangle ABC is an isosceles triangle.
Solution:
Given data:
∠ABC = 70° and ∠ACD = 55°
<em>If two parallel lines are cut by a transversal, then alternate interior angles are congruent.</em>
m∠BAC = m∠ACD
m∠BAC = 55°
<em>Sum of the angles in a straight line add up to 180°.</em>
m∠ACD + m∠ACB + m∠ABC = 180°
55° + m∠ACB + 70° = 180°
m∠ACB + 125° = 180°
Subtract 125° from both sides, we get
m∠ACB = 55°
In triangle ABC,
∠BAC = 55° and ∠ACB = 55°
∠BAC = ∠ACB
Two angles in the triangle are equal.
Therefor triangle ABC is an isosceles triangle.
5x+3y=12
Subtract 5x from both sides
3y=-5x+12
Divide by 3
Y=-5/3x +4
Answer:
3
Step-by-step explanation:
5 percent * 60 =
(5:100)* 60 =
(5* 60):100 =
300:100 = 3
Rearrange x²+y²-4x+6y=-11 I'll tell you an easy way. take the coefficient of x and divide it by -2 and the coefficient of y and divide it by -2 so -4 ÷-2 = 2 6÷-2= -3 (2,-3) is the center of the circle to know the radius √2² + -3² + -11 =√2 The Radius equals √2
Set up a proportion:
y = 35 when x = 7
y = ? when x = 10
To get x from 7 to 10, you have to multiply by 
. Therefore, you do the same to 35, and you get:
And your answer is 50 :)
