I can balance that freaking equation
1 answer:
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<u>Answer:</u> The concentration of original sulfuric acid solution is 1.62 M
<u>Explanation:</u>
Let the original concentration of sulfuric acid be 'x' M
To calculate the molarity of the diluted solution, we use the equation:
where,
are the molarity and volume of the concentrated sulfuric acid solution
are the molarity and volume of diluted sulfuric acid solution
We are given:
Putting values in above equation, we get:
Now, to calculate the concentration of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is
are the n-factor, molarity and volume of base which is NaOH.
We are given:
Putting values in above equation, we get:
Hence, the concentration of original sulfuric acid solution is 1.62 M