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Marina86 [1]
3 years ago
13

Will these changes increase, decrease, or have no effect on the mean free path of the molecules in a gas sample?

Chemistry
1 answer:
lisabon 2012 [21]3 years ago
6 0
According to the kinetic theory, the mean free path is the average distance a single atom or molecule of an element or compound travels with respect with the other atoms during a collision. The greater the mean free path, the more ideal the behavior of a gas molecule is because intermolecular forces are minimum. To understand which factors affect the mean free path, the equation is written below.

l = μ/P * √(πkT/2m), where
l is the mean free path
μ is the viscosity of the fluid
P is the pressure
k is the Boltzmann's constant
T is the absolute temperature
m is the molar mass

So, here are the general effects of the factors on the mean free path:

Mean free path increases when:
1. The fluid is viscous (↑μ)
2. At low pressures (↓P)
3. At high temperatures (↑T)
4. Very light masses (↓m)

The opposite is also true for when the mean free path decreases. Factors that are not found here have little or no effect.
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The reaction A + 2B + C -- >D + 2E is first order in reactant A, first order in B, and second order in C. What is the rate la
kvasek [131]
The answer should be D.  A rate law needs to be rate equaling the rate constant which is represented as k (make sure you use a lower case k since an upper case K is for equilibrium) times the concentrations of each reactant raised to the power of what ever order it has. (if A was a zero order it would be [A]⁰ and if A was third order it would be [A]³).
Do not get the order the reactants are confused with the coefficients in the chemical equation. (just because the reaction has 2B does not mean the rate law will have [B]².  As shown in this example since it is first order therefore being [B] in the rate law)

I hope this helps. Let me know if anything is unclear in the comments.
7 0
3 years ago
Read 2 more answers
The volume of 0.6305 kg of a liquid is 0.430 L. What is its density in g/mL
motikmotik

Answer: 1.466 g/mL

Explanation:

\frac{0.6305 \text{kg}}{0.430 \text{L}} \cdot \frac{1000 \text{g}}{1 \text{kg}} \cdot  \frac{1 \text{L}}{1000 \text{mL}} = 1.466 \,\frac{\text{g}}{\text{mL}}

6 0
2 years ago
The individual dipole moments in ammonia (NH3) do not cancel each other
kozerog [31]

Answer:

                    The strongest force that exists between molecules of Ammonia is <em>Hydrogen Bonding</em>.

Explanation:

                    Hydrogen Bond Interactions are those interactions which are formed between a partial positive hydrogen atom bonded directly to most electronegative atoms (i.e. F, O and N) of one molecule interacts with the partial negative most electronegative atom of another molecule.

                    Hence, in ammonia the nitrogen atom being more electronegative element than Hydrogen will be having partial negative charge and making the hydrogen atom partial positive. Therefore, the attraction between these partials charges will be the main force of interaction between ammonia molecules.

                  Other than Hydrogen bonding interactions ammonia will also experience dipole-dipole attraction and London dispersion forces.

4 0
3 years ago
If 10.0g of oxygen reacts with 10.0g of hydrogen, how many grams of water can be
rusak2 [61]

Answer:

the answer is 90g

Explanation:

2g of H2 produce 18g of H2O/10.0g of H2 to produce x the answer is 90g

8 0
3 years ago
Who much the velocity of a body when it travels 600m in 5 min​
Gwar [14]

Answer:

2 m/s

Explanation:

Applying the formulae of velocity,

V = d/t............. Equation 1

Where V = Velocity of the body, d = distance, t = time

From the question,

Given: d = 600 m, t = 5 minutes = (5×60) = 300 seconds.

Substitute these values into equation 1

V = 600/300

V = 2 m/s.

Hence the velocity of the body when it travels is 2 m/s

3 0
3 years ago
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