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Marina86 [1]
3 years ago
13

Will these changes increase, decrease, or have no effect on the mean free path of the molecules in a gas sample?

Chemistry
1 answer:
lisabon 2012 [21]3 years ago
6 0
According to the kinetic theory, the mean free path is the average distance a single atom or molecule of an element or compound travels with respect with the other atoms during a collision. The greater the mean free path, the more ideal the behavior of a gas molecule is because intermolecular forces are minimum. To understand which factors affect the mean free path, the equation is written below.

l = μ/P * √(πkT/2m), where
l is the mean free path
μ is the viscosity of the fluid
P is the pressure
k is the Boltzmann's constant
T is the absolute temperature
m is the molar mass

So, here are the general effects of the factors on the mean free path:

Mean free path increases when:
1. The fluid is viscous (↑μ)
2. At low pressures (↓P)
3. At high temperatures (↑T)
4. Very light masses (↓m)

The opposite is also true for when the mean free path decreases. Factors that are not found here have little or no effect.
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What do the subscripts in the formula for ethane represent?
Sedaia [141]

Answer:

the number of carbon and hydrogen atoms present in the molecule of Ethane that is it contains two carbon atoms and six hydrogen atoms

Explanation:

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2 years ago
What is the general trend for valence electrons as you go across the periodic table left to right
Margarita [4]
The atomic radius decreases across a period from left to right and increases down a given group. The atoms with the largest atomic radii are located in group l and at the bottom of groups. Moving from left to right across a period, electrons are added one at a time to the outer energy shell. Hope this helps!
6 0
3 years ago
A gas occupies 56 L at 73°C. What volume will the gas occupy if the temp. cools to 0°C?
vova2212 [387]

Answer:

44.2 L

Explanation:

Use Charles Law:

\frac{V1}{T1} =\frac{V2}{T2}

We have all the values except for V₂; this is what we're solving for. Input the values:

\frac{56 L}{346K} =\frac{V2}{273K}   -  make sure that your temperature is in Kelvin

From here, we need to get V₂ by itself. To do this, multiply by 273 on both sides:

\frac{56*273}{346} = V2

Therefore, V₂ = 44.2 L

It's also helpful to know that temperature and volume are linearly related. So, when temperature drops, so will volume and vice versa.

7 0
2 years ago
How does the flow of energy during freezing compare with the flow of energy during melting
lianna [129]

Answer:

At the melting point, some molecules overcome the forces of attraction. Energy gained after the the solid melts increases the average kinetic energy or the temperature. When liquid is freezing the energy flows out the the liquid. As the kinetic energy decreases, they move more slowly.

Explanation:

3 0
2 years ago
A given sample of a gas has a volume of 3 liters at a
ycow [4]

Answer:

B) 12

Explanation:

Given parameters:

Initial volume  = 3L

Initial pressure  = 4atm

Final pressure  = 6atm

Unknown:

Final volume  = ?

Solution:

To solve this problem, we apply Boyle's law which states that "the volume of a fixed mass of a gas varies inversely as the pressure changes if the temperature is constant".

   P₁V₁  = P₂V₂

 P and V are pressure and temperature values

 1 and 2 are initial and final states.

    PV product  = 3 x 4 = 12

7 0
3 years ago
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