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<h2>it is not dirty so do try it >:((((((</h2>
The balanced equation for the above reaction is as follows;
CaCO₃ + 2HCl ----> CaCl₂ + H₂O + CO₂
stoichiometry of CaCO₃ to HCl is 1:2
molar volume states that 1 mol of any gas occupies a volume of 22.4 L at STP.
volume of 22.4 L occupied by 1 mol
therefore 0.56 L occupied by - 0.56 L / 22.4 L/mol = 0.025 mol
number of HCl moles reacted - 0.025 mol
2 mol of HCl reacts with 1 mol of CaCO₃
therefore 0.025 mol reacts with - 0.025/2 = 0.0125 mol
mass of CaCO₃ required - 0.0125 mol x 100 g/mol = 1.25 g
1.25 g of CaCO₃ is required
Answer:
1. Students need to measure masses of the items.
2. Put baking soda and vinegar in a plastic bag and close it.
3. Mix the two, allowing for a reaction to occur.
4. Figure the mass of the plastic bag while the two components are inside.
5. The combined mass should be equal to what each weighed on their own.
Explanation:
32.066 atomic mass units.
