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Aleks [24]
3 years ago
5

What are the four states of matter?

Chemistry
2 answers:
tatuchka [14]3 years ago
6 0
Solid, liquid, gas, and plasma.
UNO [17]3 years ago
3 0
Solid, Liquid, Gas, and Plasma
You might be interested in
22. Radon has a half-life of 3.83 days. How long will it take a 225 g sample to decay to 14.06 g? (3pts.)
prohojiy [21]

Answer:

15.32 days

Explanation:

From the question given above, the following data were obtained:

Half-life (t½) = 3.83 days

Original amount (N₀) = 225 g

Amount remaining (N) = 14.06 g

Time (t) =.?

Next, we shall determine the number of half-lives that has elapsed. This can be obtained as follow:

Original amount (N₀) = 225 g

Amount remaining (N) = 14.06 g

Number of half-lives (n) =?

N = N₀ / 2ⁿ

14.06 = 225 / 2ⁿ

Cross multiply

14.06 × 2ⁿ = 225

Divide both side by 14.06

2ⁿ = 225 / 14.06

2ⁿ = 16

Express 16 in index form with 2 as the base

2ⁿ = 2⁴

n = 4

Thus, 4 half-lives has elapsed.

Finally, we shall determine the time. This can be obtained as follow:

Half-life (t½) = 3.83 days

Number of half-lives (n) = 4

Time (t) =.?

n = t / t½

4 = t / 3.83

Cross multiply

t = 4 × 3.83

t = 15.32 days

Therefore the time for 225 g sample of Radon to decay to 14.06 g is 15.32 days

8 0
3 years ago
A 1.5 M solution of NaOH was made in a laboratory. If the solution made had a volume of 4.5 L, how many grams of NaOH were added
Crank

Answer:

270g

Explanation:

Given parameters:

Concentration of NaOH  = 1.5M

Volume  = 4.5L

Unknown

Mass of NaOH added  = ?

Solution:

To solve the problem, we need to find the number of moles of the NaOH first;

 Number of moles  = concentration x volume

 Number of moles  = 1.5 x 4.5  = 6.75mol  

Now;

  Mass  = Number of moles x molar mass

 Molar mass of NaOH  = 23 + 16 + 1  = 40g/mol

  Mass  = 6.75 x 40  = 270g

6 0
3 years ago
Plz help with any you can !!!!!
EleoNora [17]
Number 1 is c. because objects reflect light we see it.
8 0
4 years ago
Read 2 more answers
1. In this experiment, what property of NaCl is used to separate it from the other two components? Is this a chemical or physica
irinina [24]

Answer 1) In the mixture of sand, NaCl and CaCO_{3} first separation was done by dissolving the mixture in water. In the first step the NaCl will get dissolved whereas, CaCO_{3} will be undissolved and sand will settle at the bottom. Here, the physical property of solubility of NaCl in water is taken into consideration. The collected water is then filtered off and evaporated to get the NaCl back from the mixture with some loss. No chemical change occurs in case of NaCl extraction from water.


Answer 2) When CaCO_{3} was to be removed from the undissolved part. The chemical property of CaCO_{3} was used. Where it gets dissolved in acidic medium. And this way we can extract CaCO_{3} and remove sand from it. We change the chemical composition of CaCO_{3} by adding HCl to the mixture and dissolve CaCO_{3} to form CaCl_{2} which gets dissolved into the solution of HCl. Here, first decantation occurs and then extraction is done. Second, extraction is done using potassium carbonate in it which separates CaCl_{2} from sand.


Answer 3) Here, Unknown mixture of salt and sand weighed =7.52 g (before washing);


Unknown mixture of salt and sand weighed =3.45 g (after washing);


To calculate the amount of salt in it, we can simply subtract the values of before and after washing change in weights.


The property of NaCl being soluble in water it will go away with washing leaving behind the sand only, after washing.


So, Weight of salt was = 7.52g - 3.45 g = 4.07g


To find the percentage of sand that was mixed with salt =

(3.45 g sand / 7.52g of mixture) X 100 = 45.9% sand was mixed with salt.


To verify whether the correct percentage of salt and sand was calculated we can recheck the value for salt as well.

(4.07 g of salt / 7.52g of mixture) X 100 = 54.1% salt


On adding we get, 45.9% + 54.1% = 100%.


Which confirms that the calculations are correct.

4 0
3 years ago
T or F? The force of attraction between a positive and negative electric charge decreases quickly as the distance between them i
agasfer [191]
False, The attraction would get stronger.
4 0
2 years ago
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