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3 years ago

determine the total water hardness in a 25.00 mL sample of water that require 12.45 ml of 0.01111m edta for titration

1 answer:

4 0

Water hardness is often expressed or defined as the content of the ions of Calcium and magnesium that make it "hard". To know the total hardness of water, EDTA titration is often used expressed as the mol of EDTA per liter of Solution.
mol of solute = (12.45 mL)(0.01111 mol/L)*(1L/1000mL)=1.3832 x 10-4.
Therefore, water hardness = 1.3832x10-4 mol/0.025 L = 5.53278x10^-3 M

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Explanation:

2Na3PO4(aq) + 2CoCl2(aq) → 2Co3(PO4)2(s) + 6NaCl(aq)

The question ask us to list the number of the kind of atom found on the left side(reactant) of the chemical equation. The question also reiterated that the order of the numbers should be the same as the order of the elements on the left side of the equation.

The type of atoms found on the left side of the equation are as follows;

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P(phosphorus atom) = 2 atoms

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Co(cobalt atom) = 2 atoms

Cl(chlorine atom) = 4 atoms

The equation on the left hand side have sodium atom, phosphorus atom, oxygen atom, cobalt atom and chlorine atom.

Note: The given equation is not balanced but it can be balanced as follows;

2Na3PO4(aq) + 3CoCl2(aq) → Co3(PO4)2(s) + 6NaCl(aq)

The balanced equation have the following number of atom on the left side:

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