Mass atomic of Ne=20.18 u
Therefore:
molar mass=20.18 g/1 mol
1 mole=6.022*10²³ particles (atoms or molecules)
Then: 6.022*10²³ atoms are contained in 20.18g
Now, We can solve this problem by the three rule.
6.022*10²³ atoms-------------------20.18 g
x------------------------------------------32 g
x=(6.022*10²³ atoms * 32 g)/20.18 g=9.55*10²³ atoms.
Answer: 9.55*10²³ Ne atoms are contained in 32 g of the element.
Answer:
Explanation:. A photograph is an image made by a photo-chemical reaction which records the impression of light on a surface coated with silver atoms. The reaction is possible due to the light-sensitive properties of silver halide crystals.
Answer:
0.03682 mL of mercury
Explanation:
We know the density of the mercury which is 13.58 g/mL
density = mass / volume
volume = mass / density
Now we can calculate the volume of 0.5 g of mercury:
volume = 0.5 / 13.58 = 0.03682 mL of mercury
