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jeyben [28]
3 years ago
13

Help with algebra pleaseee

Mathematics
2 answers:
Sati [7]3 years ago
8 0
Answer: 2

Explanation:

(3x^2 + 5x - 6) + (-x^2 + 3x + 9)

3x^2 + 5x - 6 - x^2 + 3x + 9

2x^2 + 8x + 3
maria [59]3 years ago
4 0

Answer:

option 2 is correct

mark this as brainliest!

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A Square has the vertices at (-2,6) (6,1) (1,-7) (-7,-2). At what point do the diagonals of the square intercect
DerKrebs [107]

Answer: At point (-\frac{1}{2},-\frac{1}{2})

Step-by-step explanation: <u>Diagonal</u> is a line uniting two opposite points. In a square, the diagonals intersect in a 90° and bisect each other, i.e., divides each diagonal into two segments of the same length.

In other words, the diagonals of a square meet at their midpoint, which is found as the following:

(x,y) = (\frac{x_{1}+x_{2}}{2} ,\frac{y_{1}+y_{2}}{2})

The opposite vertices of the given square are (-2,6) and (1,-7).

So, the intersection is

(x,y) = (\frac{-2+1}{2} ,\frac{6-7}{2})

(x,y) = (-\frac{1}{2},-\frac{1}{2} )

The diagonals of square with vertices (-2,6)(6,1)(1,-7)(-7,-2) intersect at point (-\frac{1}{2},-\frac{1}{2} ).

4 0
3 years ago
Which of the following is the rule for the geometric sequence 1, 3, 9, 27, . . .?
Serhud [2]

Answer:

a(n) = 1 \times  {3}^{n - 1}

Step-by-step explanation:

  • We started at 1
  • And it seems that index after index it multiplies by 3
  • The formula for the geometric sequence defined implicitly is a(n) =a(1)r^(n-1)

a(n) = a(1) {r}^{n - 1}  \\  a(n) = 1 \times  {3}^{n - 1}

6 0
3 years ago
Use a commutative property to complete the statement. mn=
n200080 [17]
The commutative property of multiplication states that u can " commute " the numbers, move them around, and the result will still be the same.
Example : 2 * 4 = 4 * 2

Therefore, mn = nm
8 0
3 years ago
Can someone help me please
shusha [124]

Answer:

-60

Step-by-step explanation:

Im smart

8 0
3 years ago
HELP PLEASE (and explain if you can <br><br>what is 5cd when c = 3 and d = 4​
rjkz [21]

<em>what is 5cd when c = 3 and d = 4</em>

<em>put</em><em> </em><em>the</em><em> </em><em>value</em><em> </em><em>c</em><em>=</em><em>3</em><em> </em><em>and</em><em> </em><em>d</em><em>=</em><em>4</em><em> </em><em>then</em><em>,</em>

<em>5</em><em>cd</em><em>=</em><em> </em><em>5</em><em> </em><em>×</em><em> </em><em>3</em><em> </em><em>×</em><em> </em><em>4</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>6</em><em>0</em><em> </em>

<em>thus</em><em> </em><em>,</em><em> </em><em>6</em><em>0</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>required</em><em> </em><em>answer</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

4 0
3 years ago
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