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3 years ago

Solve the following for equation a. 8 = a/b

Mathematics

1 answer:

ruslelena [56]3 years ago

3 0

Answer:

a=8b

Step-by-step explanation:

To do this we just need to isolate a

so we can multiply the equation by b

then we will get

a=8b

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A plane intersects both nappes of a double-napped cone but does not go through the vertex of the cone. What conic section is for

lisabon 2012 [21]

<span>When a plane intersects both nappes of a double-napped cone but does not go through the vertex of the cone, the conic section that is formed by the intersection is a curve known as hyperbola.
The standard form of the equation of the hyperbola is shown below:
[(x-h)^2/a^2]-[(y-k)^2/b^2]=1 (Horizontal axis)
</span>[(y-k)^2/a^2]-[(x-h)^2/b^2]=1 (Vertical axis)<span>
Therefore, the answer is: Hyperbola.
</span>

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3 years ago

The bowl has a diameter of 10 inches. What is its radius?

Licemer1 [7]

5 because u divide it

7 0

3 years ago

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Completely factor 7x^2 - 4x - 3

kondor19780726 [428]

Answer:

(7x+3) (x-1)

hope this helps!!:)

Step-by-step explanation:

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3 years ago

Consider the population of all 1-gallon cans of dusty rose paint manufactured by a particular paint company. Suppose that a norm

Artemon [7]

Answer:

a) 0.5.

b) 0.8413

c) 0.8413

d) 0.6826

e) 0.9332

f) 1

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 6, \sigma = 0.2$

(a) P(x > 6) =

This is 1 subtracted by the pvalue of Z when X = 6. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6-6}{0.2}$

$Z = 0$

$Z = 0$ has a pvalue of 0.5.

1 - 0.5 = 0.5.

(b) P(x < 6.2)=

This is the pvalue of Z when X = 6.2. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6.2-6}{0.2}$

$Z = 1$

$Z = 1$ has a pvalue of 0.8413

(c) P(x ≤ 6.2) =

In the normal distribution, the probability of an exact value, for example, P(X = 6.2), is always zero, which means that P(x ≤ 6.2) = P(x < 6.2) = 0.8413.

(d) P(5.8 < x < 6.2) =

This is the pvalue of Z when X = 6.2 subtracted by the pvalue of Z when X 5.8.

X = 6.2

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6.2-6}{0.2}$

$Z = 1$

$Z = 1$ has a pvalue of 0.8413

X = 5.8

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5.8-6}{0.2}$

$Z = -1$

$Z = -1$ has a pvalue of 0.1587

0.8413 - 0.1587 = 0.6826

(e) P(x > 5.7) =

This is 1 subtracted by the pvalue of Z when X = 5.7.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5.8-6}{0.2}$

$Z = -1.5$

$Z = -1.5$ has a pvalue of 0.0668

1 - 0.0668 = 0.9332

(f) P(x > 5) =

This is 1 subtracted by the pvalue of Z when X = 5.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5-6}{0.2}$

$Z = -5$

$Z = -5$ has a pvalue of 0.

1 - 0 = 1

5 0

3 years ago

Estimate the sum of 299 and 388

Svetllana [295]

For this case we have the following numbers:

299

388

Let's round up each of the numbers to the nearest hundred,

We have then:

299 = 300

388 = 400

We note that now we have two numbers whose approximation is easier to add.

We have then:

300 + 400 = 700

Answer:

The sum of 299 + 388 is approximately:

700

7 0

3 years ago

Read 2 more answers