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Brilliant_brown [7]
3 years ago
5

Kyung bought 3 CDs that cost x dollars each, 2 DVDs that cost $10 each; and a book that cost $15. Write an expression in simples

t form that represents the total amount that Kyung spent
Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
8 0

Answer:

Step-by-step explanation:

3x + 2·10 + 1·15 = (3x + 35) dollars

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sukhopar [10]

what is the question it might be an Sony-75"

6 0
3 years ago
If (-2, y) lles on the graph of y = 3^x, then y =
sweet [91]
<h3>Answer:</h3>

\frac{1}{9}

<h3>Step-by-step explanation:</h3>

We know that x=-2, so substitute that into the equation. y=3^{-2}

With negative powers, instead of making the result negative, you divide one by it.  Mathematically speaking, x^{-y}=\frac{1}{x^y}.  This makes our equation: y=\frac{1}{3^2}

Finally, simplify the exponent. y=\frac{1}{9}

8 0
4 years ago
Read 2 more answers
21 points!!
Bogdan [553]

Answer:

See attached pictures.

Step-by-step explanation:

The sine and cosine functions have the forms: f(x) = C+ A sinBx and f(x) = C + A cosBx. A is the amplitude for each function. The period is found by dividing 2π the absolute value of B or \frac{2\pi}{|B|}. C shifts the function up and down.

The sine function always starts and ends on the x-axis.

The cosine function always starts and ends at the y=A.

6.) The sine function starts at (0,0) then peaks at 5. Comes down to 0 and down to -5 before returning to 0.

The amplitude is 5.

The period is \frac{2\pi}{|2|}=\pi

7.) Here A=3 so the amplitude is 3, B is 1/2 so the period is 4π. Start at (3,0) and descend down to (2π, 0). Go back up to (4π, 3).

8.) Here A = 2 so the amplitude is A. B is 2π so the period is 1. C is 1 so the graph is shifted up a unit.

Start the graph at (0,1) and go up to (0.25,3) and down to (0.5,1) and continue downward to (0.75, -3) then back up to (1,1).

3 0
3 years ago
How can i differentiate this equation?
Dmitry_Shevchenko [17]

\bf y=\cfrac{2x^2-10x}{\sqrt{x}}\implies y=\cfrac{2x^2-10x}{x^{\frac{1}{2}}} \\\\\\ \cfrac{dy}{dx}=\stackrel{\textit{quotient rule}}{\cfrac{(4x-10)(\sqrt{x})~~-~~(2x^2-10x)\left( \frac{1}{2}x^{-\frac{1}{2}} \right)}{\left( x^{\frac{1}{2}} \right)^2}} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~(2x^2-10x)\left( \frac{1}{2\sqrt{x}} \right)}{\left( x^{\frac{1}{2}} \right)^2} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~\left( \frac{2x^2-10x}{2\sqrt{x}} \right)}{x}


\bf\cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~\left( \frac{2x^2-10x}{2\sqrt{x}} \right)}{x} \\\\\\ \cfrac{dy}{dx}=\cfrac{ \frac{(4x-10)(\sqrt{x})(2\sqrt{x})~~-~~(2x^2-10x)}{2\sqrt{x}}}{x} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})(2\sqrt{x})~~-~~(2x^2-10x)}{2x\sqrt{x}}


\bf \cfrac{dy}{dx}=\cfrac{(4x-10)2x~~-~~(2x^2-10x)}{2x\sqrt{x}}\implies \cfrac{dy}{dx}=\cfrac{8x^2-20x~~-~~(2x^2-10x)}{2x\sqrt{x}} \\\\\\ \cfrac{dy}{dx}=\cfrac{8x^2-20x~~-~~2x^2+10x}{2x\sqrt{x}} \implies \cfrac{dy}{dx}=\cfrac{6x^2-10x}{2x\sqrt{x}} \\\\\\ \cfrac{dy}{dx}=\cfrac{2x(3x-5)}{2x\sqrt{x}}\implies \cfrac{dy}{dx}=\cfrac{3x-5}{\sqrt{x}}

8 0
3 years ago
I don’t know how to answer the question
OlgaM077 [116]

Let the partitions of the segment be 5k and 3k .
.
5k+3k = length of segment
Suppose the length of segment is y
8k = y
k = y/8
.
Hence ,
5k = 5(y/8)
3k = 3(y/8)
.
As the value of the segment wasn't given , it seems a bit complicated..
.
Hope u understand!

6 0
3 years ago
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