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Fiesta28 [93]
3 years ago
7

I really need help with this question. Can I get a explanation too?

Mathematics
1 answer:
aniked [119]3 years ago
3 0

Answer:

C

Step-by-step explanation:

Find the surface area:

Bottom base: 57 × 27 = 1,539

Top base: 21 × 27 = 567

Rectangular face: 23 × 27 = 621

Rectangular face: 23 × 27 = 621

Trapezoidal face: (21 + 57) ÷ 2 × 15 = 585

Trapezoidal face: (21 + 57) ÷ 2 × 15 = 585

1,539 + 567 + 621 + 621 + 585 + 585 = 4,518

The surface area is 4,518 square inches

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Show how to use the distributive property to simplify 4(5+x).
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Answer:

Step-by-step explanation:

Ur mom

8 0
3 years ago
A palm tree casts a shadow that is 28 feet long. A 6 foot sign casts a shadow that is 8 feet long. How tall is the palm tree? Se
alukav5142 [94]

Answer:

21

Step-by-step explanation:

28/x=8/6

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4 0
3 years ago
A department​ store, on​ average, has daily sales of ​$28 comma 286.28. The standard deviation of sales is ​$1 comma 500. On​ Tu
wolverine [178]

Answer:

z-score = 4.43,

It is a Good day

Step-by-step explanation:

The provided information is:

Mean = $28,286.28

Standard deviation = $1,500

Let x be the sell of department store on Tuesday.

Then, x = $34,924.62

The z-score is define as:

z=\dfrac{x-\mu}{\sigma}\\\\=\dfrac{34924.62-28286.28}{1500}\\\\=4.43      

Thus, the Tuesday's z-score is 4.43. So this is usually good day.

3 0
3 years ago
Segments
Kazeer [188]

Given

AB  and  CD  intersect

AC,  CB,  BD  and  AD  are congruent.

Prove that AB  is the bisector of ∠CAD and ray  CD  is the bisector of ∠ACB.

and AB  and  CD  are perpendicular.

To proof

Bisector

<em>A bisector is that which cut an angle in two equal parts.</em>

In ΔACB and ΔADB

AD = AC  ( Given )

AB = AB   ( common )

BC = DB  ( Given )

by SSS congurence property

we have

ΔACB ≅ΔADB

∠CAB =∠ DAB

∠CBA = ∠DBA

( By corresponding sides of the congurent triangle )

Thus AB is the bisector of the ∠CAD.

InΔ DAC and ΔDBC

AD = DB (Given)

AC = CB  ( Given )

CD = CD (common)

By SSS congurence property

ΔDAC≅ Δ DBC

∠  ACD =∠ BCD

∠ADC =∠BDC

( By corresponding sides of the congurent triangle )

Therefore CD is the bisector of the CAD.

In ΔBOC andΔ BOD

BO = BO ( Common )

∠BCO = ∠BDO

( As prove above ΔACB ≅ΔADB

Thus ∠ACB = ∠ADB by corresponding sides of the congurent triangle , CD is a bisector

∠BCO = ∠BDO )

 CB = DB ( given )

by SAS congurence property

ΔBOC ≅ ΔBOD

∠BOC =∠ BOD

∠BOC +∠ BOD = 180 °( Linear pair )

2∠ BOC = 180°

∠BOC = 90°

∠BOC =∠ BOD = 90°

also

In ΔCOA and ΔAOD

AO = AO ( Common )

∠ACO =∠ ADO

(  As prove above ΔACB ≅ΔADB Thus ACB = ADB by corresponding sides of congurent triangle ,CD is a bisector

thus  ∠ACO = ∠ADO )

AC =AD ( given )

by SAS congurence property

Δ COA ≅ ΔAOD

∠AOC = ∠AOD

( By corresponding angle of corresponding sides )

∠AOC + ∠AOD = 180°

2∠ AOC = 180°   ( Linear pair )

∠AOC = 90°

∠AOC = ∠AOD = 90 °

Thus AB  and  CD  are perpendicular.

Hence proved









   


 



6 0
3 years ago
Please help I will give brainliest ​
valkas [14]

Answer:

choose A

Step-by-step explanation:

f6odo6d7pfp7dp6d6p

7 0
3 years ago
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