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dezoksy [38]
3 years ago
12

An electron that is in the highest energy level of an atom and determines the atom's chemical properties is called a(n)

Chemistry
1 answer:
ss7ja [257]3 years ago
3 0
The answer is C: Valence electron
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In a warehouse, the workers sometimes slide boxes along the floor to move them. Two boxes were sliding toward each other and cra
djverab [1.8K]

Answer:

There is no friction because of the mass.

Explanation:

The bigger box ran out of force to move so it hit the smaller box. (im in 7th grade and have the answer key)

5 0
3 years ago
Does a negative exponent mean that the number is less than 1 yes or no​
Masja [62]

Answer:

When a number is written in scientific notation, the exponent tells you if the term is a large or a small number. A positive exponent indicates a large number and a negative exponent indicates a small number that is between 0 and 1.

3 0
3 years ago
Convert 732.0 mmHg to atm
enot [183]

Answer:

The answer is

<h2>0.95 atm</h2>

Explanation:

To solve the question we use the following conversion

That's

1 mmHg \cong 0.0013 atm

So we have

If 1 mmHg \cong 0.0013 atm

Then 732 mmHg will be

732 × 0.0013 atm

We have the final answer as

<h3>0.95 atm</h3>

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3 years ago
Help I think the answer is either A or D.
devlian [24]

Answer:

D

Explanation:

Miss Girl. Snow isn't in Nevada-

4 0
2 years ago
Read 2 more answers
Liquid sodium is being considered as an engine coolant. How many grams of liquid sodium (minimum) are needed to absorb 1.30 MJ o
Sunny_sXe [5.5K]

Answer:

97 000 g Na

Explanation:

The absortion (or liberation) of energy in form of heat is expressed by:

q=m*Cp*ΔT

The information we have:

q=1.30MJ= 1.30*10^6 J

ΔT = 10.0°C = 10.0 K (ΔT is the same in °C than in K)

Cp=30.8 J/(K mol Na)

If you notice, the Cp in the question is in relation with mol of Na. Before using the q equation, we can find the Cp in relation to the grams of Na.

To do so, we use the molar mass of Na= 22.99g/mol

Cp= \frac{30.8J}{K*mol Na}*\frac{1 mol Na}{22.99 g Na}=1.34\frac{J}{K*g Na}

Now, we are able to solve for m:

m=\frac{1.30*10^6 J}{1.34\frac{J}{K*g Na} *10.0K}=\frac{1.30*10^6J}{13.4\frac{J}{g Na} }  = 9.70*10^4 g Na=97 Kg Na=97 000 g Na

7 0
3 years ago
Read 2 more answers
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