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sasho [114]
3 years ago
9

When would you use the Pythagorean theorem

Mathematics
2 answers:
swat323 years ago
3 0

Answer:

when you have a right angled triangle. that is when the angle is 90 degree.

Step-by-step explanation:

you will use pythagorean theorem when you have a right angled triangle. that is when the angle is 90 degree.

that is when you will have he opposite side , hypotenuse side and adjacent side.

jonny [76]3 years ago
3 0

Answer:

To find the length of the hypotenuse.

Step-by-step explanation:

You will need to know the adjacent and opposite sides to do this though. Hope this has helped you!

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Answer:

Alright well the exact form to this question is

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Step-by-step explanation:


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3 years ago
It takes 8 hours to travel 600 miles. How fast is the car traveling?
3241004551 [841]

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Step-by-step explanation:

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3 years ago
Inveres laplace transform (3s-14)/s^2-4s+8​
Olenka [21]

Complete the square in the denominator.

s^2 - 4s + 8 = (s^2 - 4s + 4) + 4 = (s-2)^2 + 4

Rewrite the given transform as

\dfrac{3s-14}{s^2-4s+8} = \dfrac{3(s-2) - 8}{(s-2)^2+4} = 3\times\dfrac{s-2}{(s-2)^2+2^2} - 4\times\dfrac{2}{(s-2)^2+2^2}

Now take the inverse transform:

L^{-1}_t\left\{3\times\dfrac{s-2}{(s-2)^2+2^2} - 4\times\dfrac{2}{(s-2)^2+2^2}\right\} \\\\ 3L^{-1}_t\left\{\dfrac{s-2}{(s-2)^2+2^2}\right\} - 4L^{-1}_t\left\{\dfrac{2}{(s-2)^2+2^2}\right\} \\\\ 3e^{2t} L^{-1}_t\left\{\dfrac s{s^2+2^2}\right\} - 4e^{2t} L^{-1}_t\left\{\dfrac{2}{s^2+2^2}\right\} \\\\ \boxed{3e^{2t} \cos(2t) - 4e^{2t} \sin(2t)}

5 0
3 years ago
10. Convert 45 miles per hour into<br> kilometers per minute.<br> Hint: 1 mile = 1.6 km
andreev551 [17]

Answer: 72km per minute

Step-by-step explanation:

Given that 1mile = 1.6km

45 mile = x

Cross multiply to find the value of x

x = 45 x 1.6km

= 72km per minute

8 0
4 years ago
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