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Mrrafil [7]
3 years ago
13

Write the expression as the sine, cosine, or tangent of an angle. cos 112° cos 45° + sin 112° sin 45°

Mathematics
2 answers:
bezimeni [28]3 years ago
7 0
The answer is cos 67°.
VARVARA [1.3K]3 years ago
6 0

Answer:

<h3>cos 112° cos 45° + sin 112° sin 45° = cos(67)°</h3>

Step-by-step explanation:

Given trigonometric expression

cos 112° cos 45° + sin 112° sin 45°

We know, the trigonometric identity

<em>cos (A-B) = cos A cos B + sin A sin B.</em>

On comparing cos 112° cos 45° + sin 112° sin 45° and cos A cos B + sin A sin B, we can see that A= 112° and B = 45°.

Plugging value A= 112° and B = 45° in cos (A-B), we get

cos ( 112- 45) = cos(67)°

<h3>Therefore, cos 112° cos 45° + sin 112° sin 45° = cos(67)°</h3>
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Solve for X 68=-52x+16
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Answer:

-1

Step-by-step explanation:

Move the +16 onto the other side. We now have 52 = -52x. Divide each side by 54 to get x = -1.

8 0
3 years ago
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Solve the following system of equations. <br> 2x + y = 3 <br> x = 2y - 1
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Show that the equation x^3+6x-5=0 has a solution between x=0 and x=1
Mnenie [13.5K]

Answer:

Since the value of f(0) is negative and the value of f(1) is positive, then there is at least one value of x between 0 and 1 for which f(x) =0.

Step-by-step explanation:

The equation f(x) given is:

f(x) = x^3+6x-5

For x = 0. the value of the expression is:

f(0) = 0^3+0-5\\f(0) = -5

For x = 1, the value of the expression is:

f(1) = 1^3+6-5\\f(1)=2

Since the value of f(0) is negative and the value of f(1) is positive, then there is at least one value of x between 0 and 1 for which f(x) =0.

In other words, there is at least one solution for the equation between x=0 and x=1.

6 0
3 years ago
Find the Missing Numerator and Denominator
n200080 [17]

Answer:

  missing denominator: 5

  missing numerator: 3

Step-by-step explanation:

You know the product of fractions is formed by multiplying numerators and multiplying denominators.

  \dfrac{3}{d}\times\dfrac{n}{4}=\dfrac{3n}{4d}=\dfrac{9}{20}

This gives rise to two equations:

  3n = 9   ⇒   n = 3

  4d = 20   ⇒   d = 5

The missing denominator is 5; the missing numerator is 3.

__

  \dfrac{3}{5}\times\dfrac{3}{4}=\dfrac{9}{20}

7 0
2 years ago
I need help please ​
saul85 [17]
Answer-44


You can turn both of the denominators ( bottom numbers on the fractions ) into 120 ( the whole number ) and the top numbers can be multiplied by how many times the denominators went into 120. Then add the top numbers which equals 76 and then 120-76=44. Hope that kinda helps !!
7 0
3 years ago
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