Yes because 2.799 has a extra digit but if there is an answer that they can be the same then they are the same
Answer:
(8a+b-16)/4
Step-by-step explanation:
1/4×3(8a-5b-4)-(4a+1)+4b
Simplify:
-4a-1+4b+1/4×3×8a-1/4×3×5b-1/4×3×4
=1/4xax24-4a-1/4bx15+4b-1/4×12-1
=1ax24/4 -4a - 1bx15/4 +4b -1×12/4 -1
=ax24/4 -4a -bx15/4 + 4b -12/4 -1
= -4a + 24a/4 + 4b - 15b/4 -1 -3
= -4a + 6a + 4b - 15b/4 - 4
= 2a + 4b - 15b/4 - 4
= 8a + 16b - 15b - 16 / 4
= (8a + b - 16) / 4
= 8a + b - 16 / 4
71 is a prime number, so the only factor pair for 71 is 1, 71.
Length=x
width=y
Perimeter of a rectangle=2(length)+2(width)
Therefore:
2x+2y=200
We simplify the equation dividend both sides of this equation by 2:
x+y=100
Then:
y=100-x
Area of a rectangle: length x width
We have the next inequation:
x(100-x)<900
100x-x²<900
x²-100x+900<0
We solve this inequation
1) we solve this equation:
x²-100x+900=0
x=[100⁺₋√(10000-3600)]/2=(100⁺₋80)/2
We have two solutions in this equation:
x₁=90
x₂=10
2)With these values, we make intervals:
(-∞,10)
(10,90)
(90,∞)
3)With these intervals, we check it out if the inequation works:
(-∞,10); for example; if x=0 ⇒ 0²-100(0)+900=100>0, this interval don´t work.
(10,90);f.e: if x=11; ⇒ 11²-100(11)+900=-79<0, this interval works.
(90,∞); fe; if x=91 ⇒91²-(100)91+900=81>0; this interval don´t work.
answer: the possible lengths would be the values inside of this interval:
(10,90) ft.
Answer:
A
Step-by-step explanation:
The rectangle has an area of 30ft^2
Each triangle has an area of 25ft^2
25+25+30=80
