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son4ous [18]
3 years ago
7

A study finds a positive correlation between the number of traffic lights on the most-used route between two destinations and th

e average driving time between the two destinations.
Which statement is true?



1.) The correlation is most likely due to a lurking variable.

2.) The correlation is most likely a coincidence.

3.) The correlation is most likely a causation.
Mathematics
1 answer:
ICE Princess25 [194]3 years ago
6 0
The correlation is most likely a causation.
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Jose received $250 for his birthday from his family. He wishes to buy a motorcycle and decides to use his birthday money towards
BartSMP [9]

Answer:

He will have $276.10 available towards the down payment for his motorcycle

Step-by-step explanation:

The compound interest formula is given by:

A = P(1 + \frac{r}{n})^{nt}

Where A is the amount of money, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per unit t and t is the time the money is invested or borrowed for.

In this problem, we have that:

P = 250, t = 2, r = 0.05

Compounded quarterly, so n = 12/4 = 3.

We have to find A.

A = P(1 + \frac{r}{n})^{nt}

A = 250(1 + \frac{0.05}{3})^{3*2}

A = 276.1

He will have $276.10 available towards the down payment for his motorcycle

8 0
2 years ago
How do you re-write 7-15 into a addition expression
Degger [83]

-15 + 7 is the addiction expression

7 0
3 years ago
Read 2 more answers
In a paper bag, 7 of the 15 marbles are yellow. In a cloth bag, 2 of the 15 marbles are yellow. If Tim randomly draws one marble
ddd [48]

Answer :

\frac{7}{15}×\frac{2}{15} = \frac{14}{225}

Step-by-step explanation:

P(Event_{1}) = choosing yellow marble from paper bag = \frac{favourable outcomes}{possible outcomes} = \frac{7}{15}

P(Event_{2}) = choosing yellow marble from cloth bag = \frac{favourable outcomes}{possible outcomes} = \frac{2}{15}

∵ Resultant outcome is dependent upon both the events and both events are independent from each other, so we can apply intersection rule [ P(A∩B)=P(A)×P(B) ] here

∴ Probability ( Both marbles are yellow) = P(Event_{1}) × P(Event_{2}) = \frac{7}{15} × \frac{2}{15}

3 0
3 years ago
Which set represents the same relation as the table below?
erik [133]

Answer:

A) { (0, 5), (4, 2), (6, 9), (9, 10)}

Step-by-step explanation:

From the table values, we can write the relation in coordinate form (x, f(x)).

The first value is x and the second value is f(x) in the coordinate.

Let's write the coordinates from the given table.

(0, 5), (4, 2), (6, 9), (9, 10)

Let's write the above coordinates in set form.

{ (0, 5), (4, 2), (6, 9), (9, 10)}

The set A is same relation as the given table.

Answer: A) { (0, 5), (4, 2), (6, 9), (9, 10)}

Hope you will understand the concept.

Thank you.

5 0
3 years ago
Read 2 more answers
onsider the following hypothesis test: H 0: 50 H a: > 50 A sample of 50 is used and the population standard deviation is 6. U
kondaur [170]

Answer:

a) z(e)  >  z(c)   2.94 > 1.64  we are in the rejection zone for H₀  we can conclude sample mean is great than 50. We don´t know how big is the population .We can not conclude population mean is greater than 50

b) z(e) < z(c)  1.18 < 1.64  we are in the acceptance region for   H₀  we can conclude H₀ should be true. we can conclude population mean is 50

c) 2.12  > 1.64 and we can conclude the same as in case a

Step-by-step explanation:

The problem is concerning test hypothesis on one tail (the right one)

The critical point  z(c) ;  α = 0.05  fom z table w get   z(c) = 1.64 we need to compare values (between z(c)  and z(e) )

The test hypothesis is:  

a) H₀      ⇒      μ₀  = 50     a)  Hₐ    μ > 50   ;    for value 52.5

                                          b) Hₐ    μ > 50   ;     for value 51

                                          c) Hₐ    μ > 50   ;      for value 51.8

With value 52.5

The test statistic    z(e)  ??

a)  z(e) =  ( μ  -  μ₀ ) /( σ/√50)      z(e) = (2.5*√50 )/6   z(e) = 2.94

2.94 > 1.64  we are in the rejected zone for H₀  we can conclude sample mean is great than 50. We don´t know how big is the population .We can not conclude population mean is greater than 50

b) With value 51

z(e) =  ( μ  -  μ₀ ) /( σ/√50)    ⇒  z(e) =  √50/6    ⇒  z(e) = 1.18

z(e) < z(c)  we are in the acceptance region for   H₀  we can conclude H₀ should be true. we can conclude population mean is 50

c) the value 51.8

z(e)  =  ( μ  -  μ₀ ) /( σ/√50)    ⇒ z(e)  = (1.8*√50)/ 6   ⇒ z(e) = 2.12

2.12  > 1.64 and we can conclude the same as in case a

8 0
3 years ago
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