Answer: Hello your question is poorly written attached below is the complete question
answer:
0.1515
Step-by-step explanation:
Number of bets = 200
mean number of losses = $0.2
Standard deviation = $2.74
<u>Determine P ( winning after 200 bets ) </u>
Average of 200 bets > 0. i.e. P( X > 0 )
considering normal distribution : μ = -0.2 , б = 2.74 , n = 200
applying Z - distribution
z = 0 - ( - 0.2 ) / ( 2.74 / √200 ) ≈ 1.03
∴ P ( z > 1.03 ) = 1 - P ( z < 1.03 )
= 1 - 0.8485 ( value gotten from z-table )
= 0.1515
