you can just split the figure in 2 separate figures and them add the areas:
area rec. 1:
3m×3m= 9m²
area rec. 2:
3m× (2m+3m)
= 3m×5m
=15m²
total area:
9m²+15m²= 24m²
Answer:
The shadow is decreasing at the rate of 3.55 inch/min
Step-by-step explanation:
The height of the building = 60ft
The shadow of the building on the level ground is 25ft long
Ѳ is increasing at the rate of 0.24°/min
Using SOHCAHTOA,
Tan Ѳ = opposite/ adjacent
= height of the building / length of the shadow
Tan Ѳ = h/x
X= h/tan Ѳ
Recall that tan Ѳ = sin Ѳ/cos Ѳ
X= h/x (sin Ѳ/cos Ѳ)
Differentiate with respect to t
dx/dt = (-h/sin²Ѳ)dѲ/dt
When x= 25ft
tanѲ = h/x
= 60/25
Ѳ= tan^-1(60/25)
= 67.38°
dѲ/dt= 0.24°/min
Convert the height in ft to inches
1 ft = 12 inches
Therefore, 60ft = 60*12
= 720 inches
Convert degree/min to radian/min
1°= 0.0175radian
Therefore, 0.24° = 0.24 * 0.0175
= 0.0042 radian/min
Recall that
dx/dt = (-h/sin²Ѳ)dѲ/dt
= (-720/sin²(67.38))*0.0042
= (-720/0.8521)*0.0042
-3.55 inch/min
Therefore, the rate at which the length of the shadow of the building decreases is 3.55 inches/min
Um I think it's like because there's a zero difference like ten thousands have more zeros
Answer:
<em>R</em>
Step-by-step explanation:
All linear functions have a range and domain of R [ALL REAL NUMBERS].
I am joyous to assist you anytime.
Answer:
- -6x² - 6 = -7x - 9
- -6x² + 7x - 6 + 9 = 0
- -6x² + 7x + 3 = 0
- 6x² - 7x - 3 = 0
<u>Discriminant:</u>
- D = (-7)² - 4*6*(-3) = 49 + 72 = 121
<u>Since D > 0, there are 2 real solutions:</u>
- x = (- (-7) ±√121 )/12
- x = (7 ± 11)/12
- x = 1.5, x = -1/3